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222-9+11+12:2*14+14 = ? ( )

Hóa học Lớp 8: câu 1: Cân bằng phương trình 1. Zn + O2 ⭢ ZnO 2. Al + AgNO3 ⭢ Al(NO3)3 + Ag 3. Mg + O2 ⭢ MgO 4. Fe2O3 + HCl ⭢ FeCl3 + H2O 5. KClO3

Hóa học Lớp 8: câu 1: Cân bằng phương trình
1. Zn + O2 ⭢ ZnO
2. Al + AgNO3 ⭢ Al(NO3)3 + Ag
3. Mg + O2 ⭢ MgO
4. Fe2O3 + HCl ⭢ FeCl3 + H2O
5. KClO3 ⭢ KCl + O2
6. Al(OH)3 + H2SO4⭢ Al2(SO4)3 + H2O
7. MgCl2 + KOH ⭢ Mg(OH)2 + KCl
8. Cu(OH)2 + HCl ⭢ CuCl2 + H2O
9. Cu(OH)2 + H2SO4 ⭢ CuSO4 + H2O
10. FeO + HCl ⭢ FeCl2 + H2O
11. Fe2O3 + H2SO4 ⭢ Fe2 (SO4)3 + H2O
12. Cu(NO3)2 + NaOH ⭢ Cu(OH)2 + NaNO3, giúp em giải bài hóa này ạ, em cảm ơn thầy cô và các bạn nhiều.

Comments ( 2 )

  1. Em tham khảo nha :
    \(\begin{array}{l}
    2Zn + {O_2} \to 2ZnO\\
    Al + 3AgN{O_3} \to Al{(N{O_3})_3} + 3Ag\\
    2Mg + {O_2} \to 2MgO\\
    F{e_2}{O_3} + 6HCl \to 2FeC{l_3} + 3{H_2}O\\
    2KCl{O_3} \to 2KCl + 3{O_2}\\
    2Al{(OH)_3} + 3{H_2}S{O_4} \to A{l_2}{(S{O_4})_3} + 3{H_2}O\\
    MgC{l_2} + 2KOH \to Mg{(OH)_2} + 2KCl\\
    Cu{(OH)_2} + 2HCl \to CuC{l_2} + 2{H_2}O\\
    Cu{(OH)_2} + {H_2}S{O_4} \to CuS{O_4} + {H_2}O\\
    FeO + 2HCl \to FeC{l_2} + {H_2}O\\
    F{e_2}{O_3} + 3{H_2}S{O_4} \to F{e_2}{(S{O_4})_3} + 3{H_2}O\\
    Cu{(N{O_3})_2} + 2NaOH \to 2NaN{O_3} + Cu{(OH)_2}
    \end{array}\)
     

  2. 1. 2Zn + O2 —> 2ZnO
    2. Al + 3AgNO3 → Al(NO3)3 + 3Ag
    3. 2Mg + O2 —-> 2MgO
    4. Fe2O3+6HCl→3H2O+2FeCl3
    5. 2KClO3→2KCl+3O2
    6. 2Al(OH)3+3H2SO4Al2(SO4)3+6H2O
    7. MgCl2 + 2KOH → Mg(OH)2 + 2KCl
    8. Cu(OH)2+2HCl→2H2O+CuCl2
    9. Cu(OH)2+H2SO4→2H2O+CuSO4
    10. FeO+2HClFeCl2+H2O
    11. Fe2O3+3H2SO4Fe2(SO4)3+3H2O
    12. Cu(NO3)2+2NaOHCu(OH)2+2NaNO3
     

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222-9+11+12:2*14+14 = ? ( )

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