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222-9+11+12:2*14+14 = ? ( )

Hóa học Lớp 9: Hoàn thành các pthh sau: a.Al Al2O3 Al2(SO4)3 Al(OH)3 Al2O3 AlCl3 b..Fe ® FeCl3 ® Fe(OH)3 ® Fe2O3 ® Fe. c/ Fe à FeSO4

Hóa học Lớp 9: Hoàn thành các pthh sau:
a.Al Al2O3 Al2(SO4)3 Al(OH)3 Al2O3 AlCl3
b..Fe ® FeCl3 ® Fe(OH)3 ® Fe2O3 ® Fe.
c/ Fe à FeSO4 à Fe (OH)2 à FeCl2 àFe(NO3 )2
d.Fe FeCl2  Fe(OH)  FeO  Fe, giúp em giải bài hóa này ạ, em cảm ơn thầy cô và các bạn nhiều.

Comments ( 1 )

  1. $a,4Al+3O_2\xrightarrow{t^o}2Al_2O_3\\ Al_2O_3+3H_2SO_4\to Al_2(SO_4)_3+3H_2O\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ 2Al(OH)_3\xrightarrow{t^o}Al_2O_3+3H_2O\\ Al_2O_3+6HCl\to 2AlCl_3+3_H2O\\ b,2Fe+3Cl_2\xrightarrow{t^o}2FeCl_3\\ FeCl_3+3NaOH\to Fe(OH)_3\downarrow+3NaCl\\ 2Fe(OH)_3\xrightarrow{t^o}Fe_2O_3+3H_2O\\ Fe_2O_3+3CO\xrightarrow{t^o}2Fe+3CO_2\\ c,Fe+H_2SO_4\to FeSO_4+H_2\\ FeSO_4+2NaOH\to Fe(OH)_2\downarrow+Na_2SO_4\\ Fe(OH)_2+2HCl\to FeCl_2+2H_2O\\ FeCl_2+2AgNO_3\to Fe(NO_3)_2+2AgCl\downarrow\\ d,Fe+2HCl\to FeCl_2+H_2\\ FeCl_2+2NaOH\to Fe(OH)_2\downarrow+2NaCl\\ Fe(OH)_2\xrightarrow{t^o}FeO+H_2O\\ FeO+H_2\xrightarrow{t^o}Fe+H_2O$

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222-9+11+12:2*14+14 = ? ( )

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