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222-9+11+12:2*14+14 = ? ( )

Hóa học Lớp 9: Viết pt thực hiện các chuỗi biến hoá sau a)Fe->FeCl3->Fe(OH)3->Fe2O3->Fe ->Fe2(SO4)3 b)Mg->MgO->MgCl2->Mg(OH)2 ->MgSO4 c)Zn->ZnO->ZnCl2

Hóa học Lớp 9: Viết pt thực hiện các chuỗi biến hoá sau
a)Fe->FeCl3->Fe(OH)3->Fe2O3->Fe
->Fe2(SO4)3
b)Mg->MgO->MgCl2->Mg(OH)2
->MgSO4
c)Zn->ZnO->ZnCl2->Zn(OH)2
->ZnSO4
d)Cu->CuCl2->Cu(OH)2->CuO
->Cu
e)Mg->MgO->MgCl2->Mg(OH)2
->MgSO4->MgCl2->Mg(NO3)2, giúp em giải bài hóa này ạ, em cảm ơn thầy cô và các bạn nhiều.

Comments ( 2 )

  1. Bạn tham khảo!
    a)
    $\text{1)2Fe+3Cl2$\xrightarrow{t^o}$2FeCl3}$
    $\text{2) FeCl3+3NaOH$\rightarrow$3NaCl+Fe(OH)3}$
    $\text{3) 2Fe(OH)3$\xrightarrow{t^o}$Fe2O3+3H2O}$
    $\text{4) Fe2O3+3CO$\xrightarrow{t^o}$2Fe+3CO2}$
    $\text{5)2Fe+6H2SO4(đặc)$\xrightarrow{t^o}$Fe2(SO4)3+3SO2+6H2O}$
    b)
    $\text{1) 2Mg+O2$\xrightarrow{t^o}$2MgO}$
    $\text{2) MgO+2HCl$\rightarrow$MgCl2+H2O}$
    $\text{3) MgCl2+2NaOH$\rightarrow$2NaCl+Mg(OH)2↓}$
    $\text{4) Mg(OH)2+H2SO4$\rightarrow$MgSO4+2H2O}$
    c)
    $\text{1) 2Zn+O2$\xrightarrow{t^o}$2ZnO}$
    $\text{2) ZnO+2HCl$\rightarrow$ZnCl2+H2O}$
    $\text{3) ZnCl2+2NaOH$\rightarrow$2NaCl+Zn(OH)2↓}$
    $\text{4) Zn(OH)2+H2SO4$\rightarrow$ZnSO4+2H2O}$
    d)
    $\text{1) CuO+2HCl$\rightarrow$CuCl2+H2O}$
    $\text{2) CuCl2+2NaOH$\rightarrow$2NaCl+Cu(OH)2↓}$
    $\text{3) Cu(OH)2$\xrightarrow{t^o}$CuO+H2O}$
    $\text{4) CuO+CO$\xrightarrow{t^o}$Cu+CO2}$
    e)
    $\text{1) 2Mg+O2$\xrightarrow{t^o}$2MgO}$
    $\text{2) MgO+2HCl$\rightarrow$MgCl2+H2O}$
    $\text{3) MgCl2+2NaOH$\rightarrow$2NaCl+Mg(OH)2↓}$
    $\text{4) Mg(OH)2+H2SO4$\rightarrow$MgSO4+2H2O}$
    $\text{5) MgSO4+BaCl2$\rightarrow$MgCl2+BaSO4↓}$
    $\text{6) MgCl2+2AgNO3$\rightarrow$2AgCl↓+Mg(NO3)2}$

  2. $\textit{Dãy chuyển hóa A}$
    1) Fe + Cl_2 FeCl_3
    2) FeCl_3 + 3NaOH →  Fe(OH)_3↓ + 3NaCl
    3) 2Fe(OH)_3 $\xrightarrow[]{to}$ Fe_2O_3 + 3H_2O
    4) Fe_2O_3 + 3H_2 $\xrightarrow[]{to}$ 2Fe + 3H_2O
    5) 2Fe + 6H_2SO_4 đ $\xrightarrow[]{to}$ Fe_2(SO_4)_3 + 3H_2O + 6SO_2↑
    $\textit{Dãy chuyển hóa B}$
    1) 2Mg + O_2 $\xrightarrow[]{to}$ 2MgO
    2) MgO + 2HCl → MgCl_2 + H_2O
    3) MgCl_2 + 2NaOH → 2NaCl + Mg(OH)_2↓ 
    4) Mg(OH)_2 + H_2SO_4 → MgSO_4 + 2H_2O
    $\textit{Dãy chuyển hóa C}$
    1) 2Zn + O_2 $\xrightarrow[]{to}$ 2ZnO
    2) ZnO + 2HCl → ZnCl_2 + H_2O
    3) ZnCl_2 + 2NaOH → 2NaCl + Zn(OH)_2 
    4) Zn(OH)_2 + H_2SO_4 → ZnSO_4 + 2H_2O
    $\textit{Dãy chuyển hóa D}$
    1) Cu + Cl_2 $\xrightarrow[]{to}$ CuCl_2 
    2) CuCl_2 + 2NaOH → Cu(OH)_2 + 2NaCl
    3) Cu(OH)_2 $\xrightarrow[]{to}$ CuO + H_2O
    4) CuO + H_2 $\xrightarrow[]{to}$ Cu + H_2O
    $\textit{Dãy chuyển hóa E}$
    1) 2Mg + O_2 $\xrightarrow[]{to}$ 2MgO
    2) MgO + 2HCl → MgCl_2 + H_2O
    3) MgCl_2 + 2NaOH → Mg(OH)_2 + 2NaCl
    4) Mg(OH)_2 + H_2SO_4 → MgSO_4 + 2H_2O
    5) MgSO_4 + BaCl_2 → MgCl_2 + BaSO_4↓
    6) MgCl_2 + 2AgNO_3 → 2AgCl↓ + Mg(NO_3)_2

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222-9+11+12:2*14+14 = ? ( )