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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: (a+b+c)^3 – a^3 – b^3-c^3 phân tích đt thành nhân tử

Toán Lớp 8: (a+b+c)^3 – a^3 – b^3-c^3
phân tích đt thành nhân tử

Comments ( 2 )

  1. Giải đáp:
    3(b+c)(a+b)(a+c)
    Lời giải và giải thích chi tiết:
    (a+b+c)³-a³-b³-c³
    =[(a+b+c)³-a³]-(b³+c³)
    =(a+b+c-a)[(a+b+c)²+(a+b+c).a+a²]-(b+c)(b²-bc+c²)
    =(b+c){[(a+b)+c]²+a²+ab+ac+a²}-(b+c)(b²-bc+c²)
    =(b+c){[(a+b)+c]²+a²+ab+ac+a²-(b²-bc+c²)}
    =(b+c)[(a+b)²+2c(a+b)+c²+a²+ab+ac+a²-b²+bc-c²]
    =(b+c)(a²+2ab+b²+2ac+2bc+c²+a²+ab+ac+a²-b²+bc-c²)
    =(b+c)[(a²+a²+a²)+(2ab+ab)+(b²-b²)+(2ac+ac)+(2bc+bc)+(c²-c²)]
    =(b+c)(3a²+3ab+3ac+3bc)
    =(b+c)[(3a²+ab)+(3ac+3bc)]
    =(b+c)[3a(a+b)+3c(a+b)]
    =(b+c)(a+b)(3a+3c)
    =3(b+c)(a+b)(a+c)

  2. (a+b+c)^3-a^3-b^3-c^3
    =[(a+b)+c]^3-a^3-b^3-c^3
    =(a+b)^3+c^3+3c(a+b)(a+b+c)-a^3-b^3-c^3
    =a^3+b^3+3ab(a+b)+3c(a+b)(a+b+c)-a^3-b^3
    =3(a+b)(ab+ac+bc+c^2)
    =3(a+b)[a(b+c)+c(b+c)]
    =3(a+b)(b+c)(c+a)

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222-9+11+12:2*14+14 = ? ( )

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