Toán Lớp 6: Tìm x:
|x+2|=1……………..
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Toán Lớp 6: Tìm x:
|x+2|=1……………..
Comments ( 2 )
|x+2|=1
⇒\(\left[ \begin{array}{l}x+2=1\\x+2=-1\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=1-2\\x=-1-2\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=-1\\x=-3\end{array} \right.\)
Vậy x∈{-1;-3}
$\left|x+2\right|=1$
\(⇒\left[ \begin{array}{l}x+2=-1\\x+2=1\end{array} \right.\) \(⇒\left[ \begin{array}{l}x=-3\\x=-1\end{array} \right.\)
Vậy $x=-3\quad \mathrm{hoặc}\quad \:x=-1$