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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Toán 9: So sánh : a, 2 và căn2 +1

Toán Lớp 9: Toán 9: So sánh : a, 2 và căn2 +1

Comments ( 2 )

  1. Ta có: $\sqrt{1}<\sqrt{2}$
    Hay $1<\sqrt{2}$
    $\to 1+1<\sqrt{2}+1$
    $\to 2<\sqrt{2}+1$
    Vậy $2<\sqrt{2}+1$
     

  2. Ta có: \sqrt{2} + 1 > \sqrt{1} + 1
    => \sqrt{2} + 1 > 1 + 1
    => \sqrt{2} + 1 > 2
    => 2 < \sqrt{2} + 1
    Vậy 2 < \sqrt{2} + 1

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222-9+11+12:2*14+14 = ? ( )