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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm x (5x-6).(1999^2+2+999+1)=(4.10^3)^2

Tháng Hai 4, 2023 Toán học 2 Comments 0 views

Toán Lớp 6: Tìm x
(5x-6).(1999^2+2+999+1)=(4.10^3)^2

Comments ( 2 )

  1. truongankimtrong
    truongankimtrong
    4 Tháng Hai, 2023 at 2:50 sáng
    Reply
    gửi tus nha
    (5x-6).(1999^2+2+999+1)=(4.10^3)^2
    (5x-6).(1999^2+1002)=(4.1000)^2
    (5x-6).(1999^2+1002)=4000^2
    (5x-6).(1999^2+1002)=16000000
    (5x-6).(3996001+1002)=16000000
    (5x-6).3997003=16000000
    (5x-6)=16000000:3997003=12002997
    5x=12002997+6
    5x=12003003
     

  2. bichhhathu
    bichhhathu
    4 Tháng Hai, 2023 at 2:49 sáng
    Reply
    (5x-6).(1999^2+2+999+1)=(4.10^3)^2
    (5x-6).(1999^2+1002)=(4.1000)^2
    (5x-6).(1999^2+1002)=4000^2
    (5x-6).(1999^2+1002)=16000000
    (5x-6).(3996001+1002)=16000000
    (5x-6).3997003=16000000
    (5x-6)=16000000:3997003=12002997
    5x=12002997+6
    5x=12003003
     
     

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222-9+11+12:2*14+14 = ? ( )

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