Toán Lớp 8: (2x^3-5x^2-x+1):(2x+1) (x^3-2x+4):(x+2) (6x^3-19x^2+23x-12):(2x-3) (x^4-2x^3-1+2x):(x^2-1) -

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Toán Lớp 8: (2x^3-5x^2-x+1):(2x+1) (x^3-2x+4):(x+2) (6x^3-19x^2+23x-12):(2x-3) (x^4-2x^3-1+2x):(x^2-1)

Huyền Thanh Tháng Hai 2, 2023 Toán học 1 Comment 0 views

Toán Lớp 8: (2x^3-5x^2-x+1):(2x+1)
(x^3-2x+4):(x+2)
(6x^3-19x^2+23x-12):(2x-3)
(x^4-2x^3-1+2x):(x^2-1)

Comments ( 1 )

maianhnhiquynh
2 Tháng Hai, 2023 at 3:29 sáng

Reply

Giải đáp:

(2x^3-5x^2-x+1):(2x+1)

=(2x^3+x^2-6x^2-3x+2x+1):(2x+1)

=[x^2(2x+1)-3x(2x+1)+2x+1]:(2x+1)

=[(2x+1)(x^2-3x+1)]:(2x+1)

=x^2-3x+1

(x^3-2x+4):(x+2)

=(x^3+8-2x-4):(x+2)

=[(x+2)(x^2-2x+4)-2(x+2)]:(x+2)

=[(x+2)(x^2-2x+2)]:(x+2)

=x^2-2x+2

(6x^3-19x^2+23x-12):(2x-3)

=(6x^3-9x^2-10x^2+15x+8x-12):(2x-3)

=[3x^2(2x-3)-5x(2x-3)+4(2x-3)]:(2x-3)

=[(2x-3)(3x^2-5x+4)]:(2x-3)

=3x^2-5x+4

(x^4-2x^3-1+2x):(x^2-1)

=(x^4-1-2x^3+2x):(x^2-1)

=[(x^2-1)(x^2+1)-2x(x^2-1)]:(x^2-1)

=[(x^2-1)(x^2-2x+1)]:(x^2-1)

=x^2+2x+1.

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