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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Phân tích đa thức thành nhân tử a) `(x+y+z)^3 – x^3 -y^3 – z^3` b) 12x^2 + 5x – 12y^2 + 12y-10xy -3`

Toán Lớp 8: Phân tích đa thức thành nhân tử
a) (x+y+z)^3 – x^3 -y^3 – z^3
b) 12x^2 + 5x – 12y^2 + 12y-10xy -3

Comments ( 2 )

  1. a) 
    (x+y+z)^3 – x^3 – y^3 – z^3
    = (x^3 + y^3 + z^3 + 3x^2y + 3xy^2 + 3x^2z+3xz^2 + 3y^2z + 3yz^2 + 6xyz) – x^3 – y^3 – z^3
    = 3x^2y + 3xy^2 + 3x^2z+3xz^2 + 3y^2z + 3yz^2 + 6xyz
    =  3(x^2y + xy^2 + x^2z + xz^2 + y^2z + yz^2 + 2xyz)
    = 3 [ (x^2y + xyz) + (xy^2 + zy^2) + (x^2z + xz^2) + (xyz + yz^2)]
    = 3 [ xy(x+z) + y^2(x+z) + xz(x+z) + yz(x+z)]
    =  3 (x+z)(xy+y^2  +xz+yz)
    = 3(x+z) [y(x+y) + z(x+y)]
    =  3(x+z)(y+z)(x+y).
    b)
    12x^2 + 5x – 12y^2 + 12y – 10xy-3
    = (12x^2 – 18xy + 9x) + (8xy – 12y^2 +  6y) + (6y – 4x -3)
    = 3x (4x – 6y + 3) + 2y (4x-6y+3) – (4x – 6y+3)
    = (3x+2y-1)(4x-6y+3).
     

  2. Giải đáp + Lời giải và giải thích chi tiết:
    a)
    (x+y+z)^3-x^3-y^3-z^3
    =x^3+y^3+z^3+3(x+y)(y+z)(z+x)-x^3-y^3-z^3
    =3(x+y)(y+z)(z+x)+(x^3-x^3)+(y^3-y^3)+(z^3-z^3)
    =3(x+y)(y+z)(z+x)
    b)
    12x^2+5x-12y^2+12y-10xy-3
    =(12x^2-18xy+9x)-(4x-6y+3)+(8xy-12y^2+6y)
    =3x(4x-6y+3)-(4x-6y+3)+2y(4x-6y+3)
    =(4x-6y+3)(3x-1+2y)
     

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222-9+11+12:2*14+14 = ? ( )