Toán Lớp 6: Tìm x biết :
3 + 2^x-1 = 24 – [ 4^2 – ( 2^2 – 1 ) ]
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Toán Lớp 6: Tìm x biết :
3 + 2^x-1 = 24 – [ 4^2 – ( 2^2 – 1 ) ]
Comments ( 2 )
3 + $2^{x-1}$ = 24 – [ 4² – (2² – 1)]
3 + $2^x$ : $2^1$ = 24 – [16 – (4 – 1)]
3 + $2^x$ : 2 = 24 – [16 – 3]
3 + $2^x$ : 2 = 24 – 13
3 + $2^x$ : 2 = 11
$2^x$ : 2 = 11 -3
$2^x$ : 2 = 8
$2^x$ = 8 × 2
$2^x$ = 16
$2^x$ = $2^4$
x = 4
Vậy x = 4
Giải đáp:
x=4
Lời giải và giải thích chi tiết:
3 + 2^(x-1) = 24 – [ 4^2 – ( 2^2 – 1 ) ]
=>3+2^(x-1)=24-[16-(4-1)]
=>3+2^(x-1)=24-[16-3]
=>3+2^(x-1)=24-13
=>3+2^(x-1)=11
=>2^(x-1)=11-3
=>2^(x-1)=8
=>2^(x-1)=2^3
=>x-1=3
=>x=3+1
=>x=4
Vậy x=4