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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: cho `f(x)=x^8-101x^7+101x^6-101x^5+…+101x^2-101x+1` Tính `f(100)`

Toán Lớp 7: cho f(x)=x^8-101x^7+101x^6-101x^5+…+101x^2-101x+1
Tính f(100)

Comments ( 2 )

  1. Với x=100 => x- 100=0
    Ta có:
    f(x) =x^8 – 101x^7 + 101x^6 -…+101x^2 -101x+1
    f(x) =x^8 – (100+1)x^7 + (100+1)x^6 -…+(100+1)x^2 – (100+1)x +1
    f(x)= x^8 – 100x^7 – x^7 +100x^6 + x^6-…+100x^2 + x^2 -100x -x +1
    f(x) = x^7(x-100) – x^6(x-100) +…+ x(x-100) – x+1
    f(x) =x^7 . 0 -x^6.0 +…+ x.0 – x+1
    f(x) = -x+1
    => f(100) = -100+1=-99
    Vậy f(100)=-99

  2. Giải đáp:
    $\\$
    Có : f (100)
    ->x=100
    ->x+1=101 (1)
    Có : f (x)= x^8 – 101x^7 + 101x^6- 101x^5 + … + 101x^2 – 101x+1
    Thay (1) vào ta được :
    -> f (x) = x^8 – (x+1)x^7 + (x+1)x^6 – (x+1)x^5  + … +(x+1)x^2 – (x+1)x+1
    -> f (x) = x^8 – x^8 – x^7 + x^7 + x^6 – x^6 – x^5 + … + x^3 + x^2 – x^2-x+1
    -> f (x) = (x^8 – x^8) + (-x^7 + x^7) + … + (x^2-x^2)+(-x+1)
    ->f(x)=-x+1
    ->f(100)=-100+1
    ->f(100)=-99
    Vậy f(100)=-99

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222-9+11+12:2*14+14 = ? ( )

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