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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: rút gọn biểu thức: A=1/√2+1 +1/√3+√2 +1/ √4+ √3

Toán Lớp 9: rút gọn biểu thức:
A=1/√2+1 +1/√3+√2 +1/ √4+ √3
B=1/√1-√2 -1/√2-√3 +1/√3-√4 -1/√4-√5 +…+1/√7-√8 -1/√8-√9

Comments ( 1 )

  1. Giải đáp:
    $A=\frac{1}{\sqrt{2}+1}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{4}+\sqrt{3}}=\frac{\sqrt{2}-1}{(\sqrt{2}+1)(\sqrt{2}-1)}+\frac{\sqrt{3}-\sqrt{2}}{(\sqrt{2}+\sqrt{3})(\sqrt{3}-\sqrt{2})}+\frac{\sqrt{4}-\sqrt{3}}{(\sqrt{4}+\sqrt{3})(\sqrt{4}-\sqrt{3})}=\sqrt{2}-1+\sqrt{3}-\sqrt{2}+\sqrt{4}-\sqrt{3}=\sqrt{4}-1$
    $B=\frac{1}{\sqrt{1}-\sqrt{2}}-\frac{1}{\sqrt{2}-\sqrt{3}}+\frac{1}{\sqrt{3}-\sqrt{4}}-\frac{1}{\sqrt{4}-\sqrt{5}}+……….+\frac{1}{\sqrt{7}-\sqrt{8}}-\frac{1}{\sqrt{8}-\sqrt{9}}=\frac{-1}{\sqrt{2}-\sqrt{1}}+\frac{1}{\sqrt{3}-\sqrt{2}}-…….-\frac{1}{\sqrt{8}-\sqrt{7}}+\frac{1}{\sqrt{9}-\sqrt{8}}=-\sqrt{2}-1+\sqrt{3}+\sqrt{2}-….-\sqrt{8}-\sqrt{7}+\sqrt{9}+\sqrt{8}=\sqrt{9}-1$  
     

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222-9+11+12:2*14+14 = ? ( )