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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: 1.Tìm x a, 4/9 + 5/6 : x = 1/6 b, 5/4 : x + 2 = 2/3 c, (1/7 – 1/3) x = 28/3 . (1/4 – 1/7) d, 13/15 – (13/21 + x) . 7/12 = 7/10 2. Tính

Toán Lớp 6: 1.Tìm x
a, 4/9 + 5/6 : x = 1/6
b, 5/4 : x + 2 = 2/3
c, (1/7 – 1/3) x = 28/3 . (1/4 – 1/7)
d, 13/15 – (13/21 + x) . 7/12 = 7/10
2. Tính
a, (15/21 : 5) : (6/5 : 2/3)
b, (8/21 . 7) : (1/3 . 6/11)
c, C = 2/3 + 2/5 – 2/9 phần 3/13 + 3/25 – 3/45

Comments ( 2 )

  1. Giải đáp:
    $\begin{array}{l}
    1)a)\dfrac{4}{9} + \dfrac{5}{6}:x = \dfrac{1}{6}\\
     \Leftrightarrow \dfrac{5}{6}:x = \dfrac{1}{6} – \dfrac{4}{9}\\
     \Leftrightarrow \dfrac{5}{6}:x = \dfrac{{ – 5}}{{18}}\\
     \Leftrightarrow x = \dfrac{5}{6}:\dfrac{{ – 5}}{{18}}\\
     \Leftrightarrow x = \dfrac{5}{6}.\dfrac{{ – 18}}{5}\\
     \Leftrightarrow x =  – 3\\
    Vậy\,x =  – 3\\
    b)\dfrac{5}{4}:x + 2 = \dfrac{2}{3}\\
     \Leftrightarrow \dfrac{5}{4}:x = \dfrac{2}{3} – 2\\
     \Leftrightarrow \dfrac{5}{4}:x = \dfrac{{ – 4}}{3}\\
     \Leftrightarrow x = \dfrac{5}{4}:\dfrac{{ – 4}}{3} = \dfrac{5}{4}.\dfrac{{ – 3}}{4}\\
     \Leftrightarrow x = \dfrac{{ – 15}}{{16}}\\
    Vậy\,x = \dfrac{{ – 15}}{{16}}\\
    c)\left( {\dfrac{1}{7} – \dfrac{1}{3}} \right).x = \dfrac{{28}}{3}.\left( {\dfrac{1}{4} – \dfrac{1}{7}} \right)\\
     \Leftrightarrow \dfrac{{ – 4}}{{21}}.x = \dfrac{{28}}{3}.\dfrac{3}{{28}}\\
     \Leftrightarrow \dfrac{{ – 4}}{{21}}.x = 1\\
     \Leftrightarrow x = \dfrac{{ – 21}}{4}\\
    Vậy\,x = \dfrac{{ – 21}}{4}\\
    2)\\
    a)\left( {\dfrac{{15}}{{21}}:5} \right):\left( {\dfrac{6}{5}:\dfrac{2}{3}} \right)\\
     = \dfrac{3}{{21}}:\left( {\dfrac{6}{5}.\dfrac{3}{2}} \right)\\
     = \dfrac{1}{7}:\dfrac{9}{5}\\
     = \dfrac{1}{7}.\dfrac{5}{9}\\
     = \dfrac{5}{{63}}\\
    b)\left( {\dfrac{8}{{21}}.7} \right):\left( {\dfrac{1}{3}.\dfrac{6}{{11}}} \right)\\
     = \dfrac{8}{3}:\dfrac{2}{{11}}\\
     = \dfrac{8}{3}.\dfrac{{11}}{2}\\
     = \dfrac{{44}}{3}\\
    c)C = \dfrac{{\dfrac{2}{3} + \dfrac{2}{5} – \dfrac{2}{9}}}{{\dfrac{3}{{15}} + \dfrac{3}{{25}} – \dfrac{3}{{45}}}}\\
     = \dfrac{{2.\left( {\dfrac{1}{3} + \dfrac{1}{5} – \dfrac{1}{9}} \right)}}{{\dfrac{3}{5}.\left( {\dfrac{1}{3} + \dfrac{1}{5} – \dfrac{1}{9}} \right)}}\\
     = \dfrac{2}{{\dfrac{3}{5}}} = \dfrac{{10}}{3}
    \end{array}$

  2. Giải đáp:
    Bài 1: Tìm x
    a, 4/9 + 5/6 : x = 1/6
    5/6 : x               = 1/6 – 4/9
    5/6 : x               = -5/18
         x                   = 5/6 : -5/18
       x                     = -3
    b, 5/4 : x + 2     = 2/3
    5/4 : x               = 2/3 – 2
    5/4 : x              = -4/3
             x              = 5/4 : -4/3
            x             =  -15/16
    c, (1/7 – 1/3) x = 28/3 . (1/4 – 1/7)
    -4/21 x           = 28/3 . 3/28
    -4/21 x           = 1
         x                 = 1 : -4/21
          x                = -21/4
    d, 13/15 – (13/21 + x) . 7/12 = 7/10
    (13/21 + x) . 7/12                 = 13/15 – 7/10
    (13/21 + x) . 7/12                  = 1/6
    13/21 + x                               = 1/6 : 7/12
      13/21 + x                               = 2/7
                    x                               = 2/7 – 13/21
                      x                             = -1/3
    Bài 2: Tính
    a, (15/21 : 5) : (6/5 : 2/3)
    = 1/7 : 9/5
    = 1/7 . 5/9
    = 5/63
    b, (8/21 . 7) : (1/3 . 6/11)
    = 8/3 : 2/11
    = 8/3. 11/2
    = 44/3
    c,
    Sửa đề:
    C = (2/3 + 2/5 – 2/9)/(3/15 + 3/25 – 3/45)
       = ( 2 . (1/3 + 1/5 – 1/9))/ ( 3/5 . (1/3 + 1/5 – 1/9))
       = 2/(3/5)
      = 10/3

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222-9+11+12:2*14+14 = ? ( )