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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: |x+y-5|+|2x-y-1|=0 |y+5|+|x-y|=0 Nhanh meeeeeeeeeeee

Toán Lớp 6: |x+y-5|+|2x-y-1|=0
|y+5|+|x-y|=0
Nhanh meeeeeeeeeeee

Comments ( 2 )

  1. Giải đáp:
    $\\$
    a,
    |x+y-5| + |2x-y-1|=0
    Với mọi x,y có : |x+y-5| ≥ 0, |2x-y-1| ≥0
    -> |x+y-5| + |2x-y-1| ≥0∀x,y
    Dấu “=” xảy ra khi :
    ↔ |x+y-5|=0, |2x-y-1|=0
    ↔x+y-5=0, 2x-y-1=0
    ↔x+y=5, 2x-y=1
    ↔x=5-y, 2x=1+y
    ↔ x =5-y, 2 (5-y)=y+1
    ↔ x = 5-y, -2y + 10=y+1
    ↔ x=5-y, -2y-y=-10+1
    ↔ x=5-y,-3y=-9
    ↔x=5-3,y=3
    ↔x=2,y=3
    Vậy (x;y) = (2;3)
    b,
    |y+5| + |x-y|=0
    Với mọi x,y có : |y+5| ≥ 0, |x-y|≥0
    -> |y+5| + |x-y| ≥0∀x,y
    Dấu “=” xảy ra khi :
    ↔ |y+5|=0, |x-y|=0
    ↔y+5=0, x-y=0
    ↔ y=-5, x=y =-5
    Vậy (x;y) = (-5;-5)

  2. Giải đáp:
    |y+5|+|x-y|=0
     Do |y+5| >= 0 AAy
           |x-y| >= 0 AAx,y
    -> |y+5|+|x-y| >= 0 AAx,y
    Dấu ”=” xảy ra <=> |y+5| = 0; |x-y| = 0
    -> y+5 = 0; x-y = 0
    -> y = -5; x+5 = 0
    -> y=-5; x = -5
    Vậy (x,y) = (-5,-5)
    |x+y-5|+|2x-y-1|=0
    Do |x+y-5| >= 0
    |2x-y-1| >= 0
    -> |x+y-5|+|2x-y-1| >= 0
    Dấu ”=” xảy ra <=> |x+y-5| = 0 ; |2x-y-1| = 0
    -> x+y-5 = 0; 2x-y-1=0
    -> x+y = 5; 2x-y = 1
    -> x = 5-y; 2(5-y) – y =1
    -> x=5-y; 10 – 2y – y =1
    -> x=5-y; 10 -3y =1
    -> x=5-y; 3y = 9
    -> x = 5-y; y =3
    -> x = 5 – 3; y=3
    -> x = 2;y=3
    Vậy (x,y) = (2,3)

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222-9+11+12:2*14+14 = ? ( )