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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: tìm x ∈ Z ( x- 1) . ( x-5 ) < 0 ( x^2 + 1) . (2x -3). ( x- 4 ) = 0

Toán Lớp 7: tìm x ∈ Z
( x- 1) . ( x-5 ) < 0 ( x^2 + 1) . (2x -3). ( x- 4 ) = 0

Comments ( 2 )

  1. ( x- 1) . ( x-5 ) < 0 
    => x-1 và x-5 là hai số nguyên cùng dấu
    Mà x – 1 > x -5
    => x – 1 > 0
    => x > 1
    => x – 5 < 0
    => x < 5
    => 1 < x < 5
    => x = 2 ; 3; 4
    ( x^2 + 1 ) (2x-3).(x-4)=0
    Mà x^2 + 1 $\neq$ 0
    => 2x-3 hoặc x – 4 =0
    => 2x-3=0
    => 2x=3
    => x = 3/2
    => x -4=0
    => x = 4

  2. a)
    (x – 1)(x – 5) < 0
    mà  x – 1 > x – 5
    ⇒ x – 1 > 0
    ⇒ x – 5 < 0
    ⇒ 5 > x > 1
    b)
    (x^2 + 1)(2x – 3)(x – 4) = 0
    text(Ta có 🙂
    x^2 + 1 = 0  (loại)
    ⇔ \(\left[ \begin{array}{l}2x – 3 = 0\\x – 4 = 0\end{array} \right.\) 
    ⇔ \(\left[ \begin{array}{l}x = 3/2\\x = 4\end{array} \right.\) 

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222-9+11+12:2*14+14 = ? ( )