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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 1. (x+5)² -x² -8 =11 2. (x+7)² -x(x+2) =13 3. (x+3)² -x² +4x =15 4. (x+9)² -x(x-4) =21 5. ( 2x + 1 )² – 4x² + 2x =-31 Giúp em vs mấy an

Toán Lớp 8: 1. (x+5)² -x² -8 =11
2. (x+7)² -x(x+2) =13
3. (x+3)² -x² +4x =15
4. (x+9)² -x(x-4) =21
5. ( 2x + 1 )² – 4x² + 2x =-31
Giúp em vs mấy anh chị ơi, mai em nộp ạ????

Comments ( 2 )

  1. Giải đáp:
    1)x=-3/5
    2)x=-3
    3)x=3/5
    4)x=-30/11
    5)x=-16/3
    Lời giải và giải thích chi tiết:
    1)(x+5)²-x²-8=11
    ⇔x²+10x+25-x²-8=11
    ⇔(x²-x²)+10x+(25-8)=11
    ⇔10x+17=11
    ⇔10x=11-17
    ⇔10x=-6
    ⇔x=-6/10
    ⇔x=-3/5
    Vậy x=-3/5
    2)(x+7)²-x(x+2)=13
    ⇔x²+14x+49-x²-2x=13
    ⇔(x²-x²)+(14x-2x)+49=13
    ⇔12x+49=13
    ⇔12x=13-49
    ⇔12x=-36
    ⇔x=(-36):12
    ⇔x=-3
    Vậy x=-3
    4)(x+9)²-x(x-4)=21
    ⇔x²+18x+81-x²+4x=21
    ⇔(x²-x²)+(18x+4x)+81=21
    ⇔22x+81=21
    ⇔22x=21-81
    ⇔22x=-60
    ⇔x=-60/22
    ⇔x=-30/11
    Vậy x=-30/11
    5)(2x+1)²-4x²+2x=-31
    ⇔4x²+4x+1-4x²+2x=-31
    ⇔(4x²-4x²)+(4x+2x)+1=-31
    ⇔6x+1=-31
    ⇔6x=-31-1
    ⇔6x=-32
    ⇔x=-32/6
    ⇔x=-16/3
    Vậy x=-16/3

  2. Giải đáp+giải thích các bước giải:
    $1. (x+5)² -x² -8 =11$
    $⇔x^2+10x+25-x^2-8=11$
    $⇔10x=11+8-25$
    $⇔10x=-6$
    $⇔x=\dfrac{-6}{10}$
    $⇔x=\dfrac{-3}{5}$
    $\text{Vậy x=}$$\dfrac{-3}{5}$
    $2. (x+7)² -x(x+2) =13$
    $⇔x^2+14x+49-x^2-2x=13$
    $⇔12x=13-49$
    $⇔12x=-36$
    $⇔x=\dfrac{-36}{12}$
    $⇔x=-3$
    $\text{Vậy x=-3}$
    $3. (x+3)² -x² +4x =15$
    $⇔x^2+6x+9-x^2+4x=15$
    $⇔10x=15-9$
    $⇔10x=6$
    $⇔x=\dfrac{6}{10}$
    $⇔x=\dfrac{3}{5}$
    $\text{Vậy x=}$$\dfrac{3}{5}$
    $4. (x+9)² -x(x-4) =21$
    $⇔x^2+18x+81-x^2+4x=21$
    $⇔22x=21-81$
    $⇔22x=-60$
    $⇔x=\dfrac{-60}{22}$
    $⇔x=\dfrac{-30}{11}$
    $\text{Vậy x=}$$\dfrac{-30}{11}$
    $5. ( 2x + 1 )² – 4x² + 2x =-31$
    $⇔4x^2+4x+1-4x^2+2x=-31$
    $⇔6x=-31-1$
    $⇔6x=-32$
    $⇔x=\dfrac{-32}{6}$
    $⇔x=\dfrac{-16}{3}$
    $\text{Vậy x=}$$\dfrac{-16}{3}$

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222-9+11+12:2*14+14 = ? ( )

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