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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Phân tích đa thức thành nhân tử: x ³-7x+6 x ³+5x ²+8x+4 x ³-9x ²+6×16 x ³-x ²-x-2 x ³+x ²-x+2 x ³-6x ²-+30

Tháng Mười Hai 29, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: Phân tích đa thức thành nhân tử:
x ³-7x+6
x ³+5x ²+8x+4
x ³-9x ²+6×16
x ³-x ²-x-2
x ³+x ²-x+2
x ³-6x ²-+30

Comments ( 2 )

  1. dinhcongson
    dinhcongson
    29 Tháng Mười Hai, 2022 at 12:52 chiều
    Reply
    x³-7x+6
    ⇒x³-x-6x+6
    ⇒x(x²-1)(x+1)-6(x-1)
    ⇒(x-1)[x(x+1)-6]
    ⇒(x-1)(x²+x-6)
    ⇒(x-1)(x²-2x+3x-6)
    ⇒(x-1)(x-2)(x-3)
    x³+5x²+8x+4
    ⇒x³+2x²+3x²+6x+2x+4
    ⇒x²(x+2)+3x(x+2)+2(x+2)
    ⇒(x+2)(x²+3x+2)
    ⇒(x+2)(x²+x+2+2x)
    ⇒(x+2)[x(x+1)+2(x+1)]
    ⇒(x+2)(x+1)(x+2)
    ⇒(x+2)²(x+1)
    x³-9x²+6×16
    ⇒x³-9x²+96x
    ⇒x(x²-9x+96)
    x³-x²-x-2
    ⇒x³-2x²+x²-2x+x-2
    ⇒x²(x-2)+x(x-2)+(x-2)
    ⇒(x-2)(x²+x+1)
    x³+x²-x+2
    ⇒x³+2x²-x²-2x+x+2
    ⇒x²(9x+2)-x(x+2)+(x+2)
    ⇒(x+2)(x²-x+1)

  2. tongtung
    tongtung
    29 Tháng Mười Hai, 2022 at 12:52 chiều
    Reply
    x^3 – 7x+6
    =x^3 – x – 6x + 6
    =x(x^2 – 1) – 6 ( x -1 )
    =x ( x – 1)(x + 1) – 6 ( x – 1)
    =(x – 1)[x(x + 1) – 6]
    =(x – 1)(x^2 + x – 6)
    =(x – 1)(x^2 – 2x + 3x – 6)
    =(x- 1)(x – 2)(x + 3)
    x^3 + 5x^2  + 8x + 4
    =x^3  + 2x^2 + 3x^2 + 6x + 2x + 4
    =x^2(x + 2) + 3x ( x + 2) + 2 ( x + 2)
    =(x + 2)(x^2 + 3x + 2)
    =(x + 2)(x^2 + x + 2x + 2)
    =(X + 2) [x ( x + 1) + 2(x + 1)]
    =(x + 2)(x + 1)(x + 2)
    =(x + 2)^2 . (x + 1)
    x^3 – 9x^2 + 6×16
    =x^3 – 9x^2 + 96x
    =x ( x^2 – 9x + 96)
    x ³- x ²- x – 2
    =x^3 – 2x^2 + x^2 – 2x + x – 2
    =x^2 ( x – 2) + x ( x – 2) + ( x – 2)
    =(x – 2)(x^2 + x + 1)
    x^3 + x^2 – x + 2
    =x^3 + 2x^2 – x^2 – 2x + x + 2
    =x^2 ( x + 2) – x (x + 2) + (x + 2)
    = (x + 2)(x^2 – x + 1)
    x ³-6x ²-+30
     

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222-9+11+12:2*14+14 = ? ( )

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