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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Rút gọn các biểu thức sau: a) 2x(2x − 1)2 − 3x(x + 3)(x − 3) − 4x(x + 1)2 b) (a − b + c) 2 − (b − c) 2 + 2ab − 2ac. c) (3x + 1)2 − 2(3x

Toán Lớp 8: Rút gọn các biểu thức sau:
a) 2x(2x − 1)2 − 3x(x + 3)(x − 3) − 4x(x + 1)2
b) (a − b + c) 2 − (b − c) 2 + 2ab − 2ac.
c) (3x + 1)2 − 2(3x + 1)(3x + 5) + (3x + 5)2.
d) 4(32 + 1)(34 + 1)(38 + 1)(316 + 1)(332 + 1).

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
     a)2x(2x-1)^2-3x(x+3)(x-3)-4x(x+1)^2
    =2x(4x^2-4x+1)-3x(x^2-9)-4x(x^2+2x+1)
    =8x^3-8x^2+2x-3x^3+27x-4x^3-8x^2-4x
    =x^3-16x^2+25x
    b)(a-b+c)^2-(b-c)^2+2ab-2ac
    =a^2+b^2+c^2-2ab-2bc+2ac-b^2+2bc-c^2+2ab-2ac
    =a^2
    c)(3x+1)^2-2(3x+1)(3x+5)+(3x+5)^2
    =(3x+1-3x-5)^2
    =(-4)^2
    =16
    d)4(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)
    =(8(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1))/2
    =((3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1))/2
    =((3^4-1)(3^4+1)(3^8+1)(3^16+1)(3^32+1))/2
    =((3^8-1)(3^8+1)(3^16+1)(3^32+1))/2
    =((3^16-1)(3^16+1)(3^32+1))/2
    =((3^32-1)(3^32+1))/2
    =(3^64-1)/2

  2. a)2x(2x-1)²-3x(x+3)(x-3)-4x(x+1)²
    =2x(4x²-4x+1)-3x(x²-9)-4x(x²+2x+1)
    =8x³-8x²+2x-3x³+27x-4x³-8x²-4x
    =(8x³-3x³-4x³)+(-8x²-8x²)+(2x+27x-4x)
    =x³-16x²+25x
    b)(a-b+c)²-(b-c)²+2ab-2ac
    =(a-b+c+b-c)(a-b+c-b+c)+2ab-2ac
    =a(a-2b+2c)+2ab-ac
    =a²-2ab+2ac+2ab-2ac
    =a²+(-2ab+2ab)+(2ac-2ac)
    =a²
    c)(3x+1)²-2(3x+1)(3x+5)+(3x+5)²
    =[(3x+1)-(3x+5)]²
    =(3x+1-3x-5)²
    =(-4)²
    =16
    d)4(3²+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)
    =[8(3²+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)]/2
    =[(3^2-1)(3²+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)]/2
    =[[(3^2)^2-1^2](3^4+1)(3^8+1)(3^16+1)(3^32+1)]/2
    =[(3^4-1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)]/2
    =[[(3^4)^2-1^2](3^8+1)(3^16+1)(3^32+1)]/2
    =[(3^8-1)(3^8+1)(3^16+1)(3^32+1)]/2
    =[[(3^8)^2-1^2](3^16+1)(3^32+1)]/2
    =[(3^16-1)(3^16+1)(3^32+1)]/2
    =[[(3^16)^2-1^2](3^32+1)]/2
    =[(3^32-1)(3^32+1)]/2
    =[(3^32)^2-1^2]/2
    =(3^64-1)/2

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222-9+11+12:2*14+14 = ? ( )

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