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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 1) (x+2)^2 + (3-x)^2 2) (4-x)^2 – (x-3)^2 3) (x-5) (x+5) – (x+5)^2 4) (x-3)^2 – (x-4) (x+4) 5) (y^2 – 6y + 9) – (3- y)^2 6)(2x + 3)^2 –

Home/ Toán Lớp 8: 1) (x+2)^2 + (3-x)^2 2) (4-x)^2 – (x-3)^2 3) (x-5) (x+5) – (x+5)^2 4) (x-3)^2 – (x-4) (x+4) 5) (y^2 – 6y + 9) – (3- y)^2 6)(2x + 3)^2 –

Toán Lớp 8: 1) (x+2)^2 + (3-x)^2 2) (4-x)^2 – (x-3)^2 3) (x-5) (x+5) – (x+5)^2 4) (x-3)^2 – (x-4) (x+4) 5) (y^2 – 6y + 9) – (3- y)^2 6)(2x + 3)^2 –

Tháng Mười Hai 20, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: 1) (x+2)^2 + (3-x)^2
2) (4-x)^2 – (x-3)^2
3) (x-5) (x+5) – (x+5)^2
4) (x-3)^2 – (x-4) (x+4)
5) (y^2 – 6y + 9) – (3- y)^2
6)(2x + 3)^2 – (2x – 3) (2x +3)
giúp mình trong tối nay ạ!!

Comments ( 2 )

  1. annhocbichchaubich
    annhocbichchaubich
    20 Tháng Mười Hai, 2022 at 1:48 sáng
    Reply
    Giải đáp:
    1)2x²-2x+13
    2)7-2x
    3)-10x-50
    4)-6x+25
    5)0
    6)12x+18
    Lời giải và giải thích chi tiết:
    1)(x+2)²+(3-x)²
    =x²+4x+4+9-6x+x²
    =(x²+x²)+(4x-6x)+(4+9)
    =2x²-2x+13
    2)(4-x)²-(x-3)²
    =[(4-x)+(x-3)][(4-x)-(x-3)]
    =(4-x+x-3)(4-x-x+3)
    =1.(7-2x)
    =7-2x
    3)(x-5)(x+5)-(x+5)²
    =(x+5)[(x-5)-(x+5)]
    =(x+5)(x-5-x-5)
    =(x+5).(-10)
    =-10x-50
    4)(x-3)²-(x-4)(x+4)
    =x²-6x+9-(x²-16)
    =x²-6x+9-x²+16
    =(x²-x²)-6x+(9+16)
    =-6x+25
    5)(y²-6y+9)-(3-y)²
    =(y-3)²-(3-y)²
    =[(y-3)+(3-y)][(y-3)-(3-y)]
    =(y-3+3-y)(y-3-3+y)
    =0.(2y-6)
    =0
    6)(2x+3)²-(2x-3)(2x+3)
    =(2x+3)[(2x+3)-(2x-3)]
    =(2x+3)(2x+3-2x+3)
    =(2x+3).6
    =12x+18

  2. doanthulan
    doanthulan
    20 Tháng Mười Hai, 2022 at 1:47 sáng
    Reply
    Giải đáp + Lời giải và giải thích chi tiết:
    1. (x+2)^2+(3-x)^2
    =x^2+4x+4+9-6x+x^2
    =2x^2-2x+13
    2. (4-x)^2-(x-3)^2
    =[(4-x)-(x-3)][(4-x)+(x-3)]
    =(4-x-x+3)(4-x+x-3)
    =(7-2x)*1=7-2x
    3. (x-5)(x+5)-(x+5)^2
    =(x+5)[(x-5)-(x+5)]
    =(x+5)(x-5-x-5)
    =(x+5)(-10)=-10x-50
    4. (x-3)^2-(x-4)(x+4)
    =x^2-6x+9-(x^2-16)
    =x^2-6x+9-x^2+16=-6x+25
    5. y^2-6y+9-(3-y)^2
    =(y-3)^2-(3-y)^2
    =[(y-3)-(3-y)][(y-3)+(3-y)]
    =(y-3-3+y)(y-3+3-y)
    =(2y-6)*0=0
    6. (2x+3)^2-(2x-3)(2x+3)
    =(2x+3)[(2x+3)-(2x-3)]
    =(2x+3)(2x+3-2x+3)
    =(2x+3)*6=12x+18.
     

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222-9+11+12:2*14+14 = ? ( )

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