Toán Lớp 8: Cộng các phân thức sau
x + x^2+1/1-x +1
4/x+2 + 3/2-x^2 +12/x^4 -4
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Toán Lớp 8: Cộng các phân thức sau
x + x^2+1/1-x +1
4/x+2 + 3/2-x^2 +12/x^4 -4
Comments ( 1 )
$=x^2+2$
———————
$=\dfrac{4}{x}-x^2+\dfrac{12}{x^4}-\dfrac{1}{2}$