Toán Lớp 7: (x+1)/2021 +(x+2) /20122= (x+3)/2023+ (x+4)/2024

Question

Toán Lớp 7:  (x+1)/2021 +(x+2) /20122= (x+3)/2023+ (x+4)/2024

tuyen98 · Answer

$ text{(☞ﾟヮﾟ)☞  Uy t&iacute;n nha  ☜(ﾟヮﾟ☜)}$   $ text{&copy; Bản quyền thuộc về youtubehieuvip22}$    $ text{&copy; Copyright by Hieuvip22 ☞ Do not Reup}$        (x+1)/2021 +(x+2) /2022= (x+3)/2023+ (x+4)/2024   (x+1)/2021 -1+(x+2) /2022 -1= (x+3)/2023 -1+ (x+4)/2024 -1   (x-2020)/2021+(x-2020)/2022=(x-2020)/2023+(x-2020)/2024   (x-2020)(1/20212021+1/2022-1/2023-1/2024)=0   => x=2020   $ text{V&igrave;}$     1/20212021+1/2022-1/2023-1/2024>0

baoquyen · Answer

(x+1)/2021+(x+2)/2022=(x+3)/2023+(x+4)/2024   &hArr;(x+1)/2021-1+(x+2)/2022-1=(x+3)/2023-1+(x+4)/2024-1   &hArr;(x+1-2021)/2021+(x+2-2022)/2022=(x+3-2023)/2023+(x+4-2024)/2024   &hArr;(x-2020)/2021+(x-2020)/2022-(x-2020)/2023-(x-2020)/2024=0   &hArr;(x-2020)(1/2021+1/2022-1/2023-1/2024)=0   &hArr;x-2020=0   &hArr;x=2020   Vậy x=2020