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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: a,A= 1+2+2^2+2^3+ …+ 2^100 b, B= 3^200+3^198+3^196+…+ 3^2+ 1 c, C =1/4+ 1/4^2 + 1/4^3 + … + 1/4^2021 d, D= 1/5 + (1/5) ^ 3 + ( 1

Home/ Toán Lớp 6: a,A= 1+2+2^2+2^3+ …+ 2^100 b, B= 3^200+3^198+3^196+…+ 3^2+ 1 c, C =1/4+ 1/4^2 + 1/4^3 + … + 1/4^2021 d, D= 1/5 + (1/5) ^ 3 + ( 1

Toán Lớp 6: a,A= 1+2+2^2+2^3+ …+ 2^100 b, B= 3^200+3^198+3^196+…+ 3^2+ 1 c, C =1/4+ 1/4^2 + 1/4^3 + … + 1/4^2021 d, D= 1/5 + (1/5) ^ 3 + ( 1

Tháng Mười Hai 10, 2022 Toán học 2 Comments 0 views

Toán Lớp 6: a,A= 1+2+2^2+2^3+ …+ 2^100
b, B= 3^200+3^198+3^196+…+ 3^2+ 1
c, C =1/4+ 1/4^2 + 1/4^3 + … + 1/4^2021
d, D= 1/5 + (1/5) ^ 3 + ( 1/5) ^5 +…+ (1/5) ^2021
e, E= 3^100- 3^99+ 3^98 – 3^97 + …+ 3^2 – 3 + 3^0

Comments ( 2 )

  1. maianhnhiquynh
    maianhnhiquynh
    10 Tháng Mười Hai, 2022 at 7:39 chiều
    Reply
    Giải đáp:
     
    Lời giải và giải thích chi tiết:
    a, A = 1 + 2 + 2^2 +………..+ 2^100
        2A = 2 + 2^2 + 2^3 +……….+ 2^101
        2A – A = ( 2 + 2^2 + 2^3 +……….+ 2^101 ) – ( 1 + 2 + 2^2 +………..+ 2^100 )
        A = 2^101 – 1
    b, B = 3^200 + 3^198 + 3^196 +…….+ 3^2 + 1
        3^2B = 3^202 + 3^200 + 3^198 +…….+ 3^4 + 3^2
        9B – B = ( 3^202 + 3^200 + 3^198 +…….+ 3^4 + 3^2 ) – ( 3^200 + 3^198 + 3^196 +…….+ 3^2 + 1 )
        8B = 3^202 – 1
        B = ( 3^202 – 1 )/8
    c, C = 1/4 + 1/4^2 + 1/4^3 +………..+ 1/4^2021
       1/4C = 1/4^2 + 1/4^3 + 1/4^4 +………+ 1/4^2022
       C – 1/4C = ( 1/4 + 1/4^2 + 1/4^3 +………..+ 1/4^2021 ) – ( 1/4^2 + 1/4^3 + 1/4^4 +………+ 1/4^2022 )
       3/4C = 1/4 – 1/4^2022
       C = ( 1/4 – 1/4^2022 ) : 3/4
       C = ( 1/4 – 1/4^2022 ) . 4/3
       C = 1/3 – 1/( 4^2021 . 3 )
    d, D = 1/5 + 1/5^3 + 1/5^5 +………+ 1/5^2021
        1/5^2D = 1/5^3 + 1/5^5 + 1/5^7 +……..+ 1/5^2023
        D – 1/5D = ( 1/5 + 1/5^3 + 1/5^5 +………+ 1/5^2021 ) – ( 1/5^3 + 1/5^5 + 1/5^7 +……..+ 1/5^2023 )
        4/5D = 1/5 – 1/5^2023
        D = 1/4 – 1/( 5^2022 . 4 )
    e, E = 3^100 – 3^99 + 3^98 -………….- 3 + 1
        3E = 3^101 – 3^100 + 3^99 -………..- 3^2 + 3
        3E + E = ( 3^101 – 3^100 + 3^99 -………..- 3^2 + 3 ) + ( 3^100 – 3^99 + 3^98 -………….- 3 + 1 )
        4E = 3^101 + 1
        E = ( 3^101 + 1 )/4 

  2. dantam45
    dantam45
    10 Tháng Mười Hai, 2022 at 7:39 chiều
    Reply
    a)
    A = 1 + 2 + 2^2 + ………… + 2^100
    2A = 2 + 2^2 + …………… + 2^101
    A = 2^101 – 1
    b)
    B = 3^200 + 3^198 + ………… + 3^2 + 1
    9B = 3^202 + 3^200 + ………. + 3^4 + 3^2
    8B = 3^202 – 1
    B = (3^202 – 1) : 8
    c)
    C = 1/4 + 1/(4^2) + ………… + 1/(4^2021)
    4C = 1 + 1/4 + …………….. + 1/(4^2020)
    3C = 1 – 1/(4^2021)
    C = (1 – 1/(4^2021)) : 3
    d)
    D = 1/5 + (1/5)^3 + …………… + (1/5)^2021
    1/25D = (1/5)^3 + ( 1/5)^5 +…+ (1/5)^2023
    24/25D = 1 – (1/5)^2023
    D = [1 – (1/5)^2023] : 24/25
    e)
    E= 3^100- 3^99+ 3^98 – 3^97 + ………………+ 3^2 – 3 + 3^0
    3E = 3^101 – 3^100 + 3^99 – 3^98 + …………… + 3^3 – 3^2 + 3^1
    4E = 3^101 + 1
    E = (3^101 + 1) : 4

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222-9+11+12:2*14+14 = ? ( )

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