Toán Lớp 6: Tìm x
|x|=|1/1.2+1/2.3+…+1/99.100|
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Toán Lớp 6: Tìm x
|x|=|1/1.2+1/2.3+…+1/99.100|
Comments ( 2 )
|x|=|1-1/2+1/2-1/3+…+1/99-1/100|
|x|=|1-1/100|
|x|=|100/100-1/100|
|x|=|99/100|
|x|=99/100
=>\(\left[ \begin{array}{l}x=\frac{99}{100}\\x=\frac{-99}{100}\end{array} \right.\)
Vậy x in {99/100;-99/100}