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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: BT1:giải các pt sau a)(3x – 5)(4x +2)= 0 b) 3x-2/x+7 = 6x+1/2x-3 c) /4x/ = 2x + 12 gấp!!!

Toán Lớp 9: BT1:giải các pt sau
a)(3x – 5)(4x +2)= 0
b) 3x-2/x+7 = 6x+1/2x-3
c) /4x/ = 2x + 12
gấp!!!

Comments ( 2 )

  1. a)
    (3x – 5)(4x + 2) = 0
    ⇒ \(\left[ \begin{array}{l}3x – 5 = 0\\4x + 2 = 0\end{array} \right.\) 
    ⇒ \(\left[ \begin{array}{l}x = 5/3\\x = -1/2\end{array} \right.\) 
    Vậy  S = {5/3 ; -1/2}
    b)
    (3x – 2)/(x + 7) = (6x + 1)/(2x – 3)
    ⇒ ((3x – 2)(2x – 3))/((x + 7)(2x – 3)) = ((6x + 1)(x + 7))/((x + 7)(2x – 3))
    ⇔ (3x – 2)(2x – 3) = (6x + 1)(x + 7)
    ⇔ 6x^2 – 13x + 6 = 6x^2 + 43x + 7
    ⇔ 6x^2 – 6x^2 – 13x – 43x = 7 – 6
    ⇔ -56x = 1
    ⇒ x = -1/56
    Vậy  S = {-1/56}
    c)
    |4x| = 2x + 12
    Với  x ≥ 0
    ⇒ 4x = 2x + 12
    ⇔ 2x = 12
    ⇒ x = 6  ™
    Với  x < 0
    ⇒ -4x = 2x + 12
    ⇔ -6x = 12
    ⇒ x = -2  ™
    Vậy  S = {6;-2}

  2. Giải đáp:
     
    Lời giải và giải thích chi tiết:
     a) (3x – 5)(4x +2)= 0
    ⇔ \(\left[ \begin{array}{l}3x-5=0\\4x+2=0\end{array} \right.\)
    ⇔ \(\left[ \begin{array}{l}3x=5\\4x=-2\end{array} \right.\)
    ⇔ \(\left[ \begin{array}{l}x=\dfrac{5}{3}\\x=-\dfrac{1}{2}\end{array} \right.\)
    Vậy S={5/3;-1/2}
    b) (3x-2)/(x+7) = (6x+1)/(2x-3)
    ĐK: x \ne -7, x \ne 3/2
    ⇔ (3x-2)(2x-3)=(6x+1)(x+7)
    ⇔ 6x^2-9x-4x+6=6x^2+42x+x+7
    ⇔ 56x=-1
    ⇔ x=-1/56\ (TM)
    Vậy S={-1/56}
    c) |4x| = 2x + 12 
    TH1: x \ge 0
    4x=2x+12
    ⇔ 4x-2x=12
    ⇔ 2x=12
    ⇔ x=6\ (TM)
    TH2: x<0
    4x=-2x-12
    ⇔ 4x+2x=-12
    ⇔ 6x=-12
    ⇔ x=-2\ (TM)
    Vậy S={-2;6}

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222-9+11+12:2*14+14 = ? ( )