Toán Lớp 8: Tìm x , biết : x³ - 9x² + 27x - 27 = 0

x³-9x²+27x-27=0 (x-3)³=0 x-3=0 x=3

$x^3-9x^2+27x-27=0 ↔x^3-3.x^2.3+3.x.3^2-3^3=0 ↔(x-3)^3=0 ↔x-3=0 ↔x=3$ Vậy $x=3$

Toán Lớp 8: Tìm x , biết : x³ - 9x² + 27x

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