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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Chứng minh đẳng thức sau: $(a+b+c)^{2}$ + $a^{2}$ + $b^{2}$ + $c^{2}$ = $(a+b)^{2}$ + $(b+c)^{2}$ + $(c+a)^{2}$

Toán Lớp 8: Chứng minh đẳng thức sau: $(a+b+c)^{2}$ + $a^{2}$ + $b^{2}$ + $c^{2}$ = $(a+b)^{2}$ + $(b+c)^{2}$ + $(c+a)^{2}$

Comments ( 2 )

  1. #Sad
    \text{→Chứng minh:}
    (a+b+c)^2+a^2+b^2+c^2 = (a+b)^2+(b+c)^2+(c+a)^2
    \text{Ta có:}
    \text{VT} = (a+b+c)^2+a^2+b^2+c^2
    = (a+b+c)(a+b+c)+a^2+b^2+c^2
    = a^2+ab+ac+ab+b^2+bc+ac+bc+c^2+a^2+b^2+c^2
    = (a^2+ab+ab+b^2)+(b^2+bc+bc+c^2)+(c^2+ac+ac+a^2)
    = (a^2+2ab+b^2)+(b^2+2bc+c^2)+(c^2+2ac+a^2)
    = (a+b)^2+(b+c)^2+(c+a)^2 = \text{VP} \text{(→đpcm)}
    \text{→Áp dụng:} (A+B)^2 = A^2+2AB+B^2
     

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222-9+11+12:2*14+14 = ? ( )