Toán Lớp 9: Tam giác ABC vuông tại A, AB = 30cm; tan B = 5/12. Tính BC, AC
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Toán Lớp 9: Tam giác ABC vuông tại A, AB = 30cm; tan B = 5/12. Tính BC, AC
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$tanB=\dfrac{AC}{AB}=\dfrac{5}{12}$
$⇒AC=AB.\dfrac{5}{12}=30.\dfrac{5}{12}=12,5(cm)$
$AB^2+AC^2=BC^2(Ptg)$