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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Giải phương trình sau đây : a) 8( 3x – 2 ) – 14x = 2( 4 – 7x ) + 15x b) ( 3x – 1 )( x – 3 ) – 9 + x^2 = 0 c) |x-2| = 2x-3

Toán Lớp 8: Giải phương trình sau đây :
a) 8( 3x – 2 ) – 14x = 2( 4 – 7x ) + 15x
b) ( 3x – 1 )( x – 3 ) – 9 + x^2 = 0
c) |x-2| = 2x-3

Comments ( 2 )

  1. a)
    8(3x-2)-14x=2(4-7x)+15x
    <=>24x-16-14x=8-14x+15x
    <=>24x-14x+14x-15x=8+16
    <=>9x=24
    <=>x=8/3
    vậy x={8/3}
    b)
    (3x-1)(x-3)-9+x^2=0
    <=>3x^2-9x-x+3-9+x^2=0
    <=>4x^2-10x-6=0
    <=>(x-3)(4x+2)=0
    <=> \(\left[ \begin{array}{l}x-3=0\\4x+2=0\end{array} \right.\) <=>\(\left[ \begin{array}{l}x=3\\4x=-2\end{array} \right.\) <=> \(\left[ \begin{array}{l}x=3\\x=\dfrac{-1}{2}\end{array} \right.\) 
    vậy S={3;-1/2}
    |x-2|=2x-3
    TH1: x-2>0=>x>2 
    x-2=2x-3
    <=>x-2x=-3+2
    <=>-x=-1
    <=>x=1 (l)
    TH2: x-2<0=>x<2
    x-2=-2x+3
    <=>x+2x=3+2
    <=>3x=5
    <=>x=5/3 ™
    vậy S={5/3} 

  2. Giải đáp + Lời giải và giải thích chi tiết:
    a) 8( 3x – 2 ) – 14x = 2( 4 – 7x ) + 15x
    => 24x – 16 -14x = 8 – 14x + 15x
    => 10x -16 = 8 + x
    => 9x = 24
    => x = $\frac{24}{9}$ 
    b) ( 3x – 1 )( x – 3 ) – 9 + x2 = 0
    =>(3x -1)( x – 3) + (x – 3)(x + 3) = 0
    => (x – 3)(3x – 1 + x – 3) = 0
    => (x – 3)(4x + 2) = 0
    => \(\left[ \begin{array}{l}x-3=0\\4x+2=0\end{array} \right.\)
    => \(\left[ \begin{array}{l}x=3\\x=\frac{-1}{2}\end{array} \right.\) 
    c) |x – 2| = 2x – 3
    TH1: x – 2 ≥ 0 => x ≥ 2
    Khi đó: x – 2 = 2x – 3
    => 2x – x = -2 + 3
    => x = 1 (không thoả mãn điều kiện x ≥ 2)
    TH2: x – 2 < 0 => x < 2
    Khi đó: x – 2 = -(2x – 3)
    => x – 2 = -2x + 3
    => 3x = 5
    => x = $\frac{5}{3}$  (thoả mãn điều kiện x < 2)

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222-9+11+12:2*14+14 = ? ( )