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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: A, x (x+3)=0 B, (x-2)(5-x)=0 C,(x-1)(x mũ 2+1)=0

Toán Lớp 7: A, x (x+3)=0
B, (x-2)(5-x)=0
C,(x-1)(x mũ 2+1)=0

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
     a)x (x+3)=0
    $\left[\begin{matrix} x=0\\x+3=0\end{matrix}\right.$=>$\left[\begin{matrix} x=0\\ x=0-3=-3\end{matrix}\right.$
    Vậy x=0;-3
    b)(x-2)(5-x)=0
    $\left[\begin{matrix} x-2=0\\5-x=0\end{matrix}\right.$=>$\left[\begin{matrix} x=0+2=2\\x=5-0=5 \end{matrix}\right.$
    Vậy x=2;5
    c)(x-1)(x^2+1)=0
    $\left[\begin{matrix} x-1=0\\ x^2+1=0\end{matrix}\right.$=>$\left[\begin{matrix} x=0+1=1\\ x^2=0-1=(-1)^2=1\end{matrix}\right.$
    Vậy x=1

  2. A. x (x+3)=0
    <=> x^2 +3x=0
    <=> (x+0)(x+3)=0
    TH1: 
    <=> x+0=0
    <=> x=0
    TH2:
    <=> x+3=0
    <=> x=-3
    => x∈{0;-3}
    B. (x-2)(5-x)=0
    TH1:
    <=> x-2=0
    <=> x=2
    TH2:
    <=> 5-x=0
    <=> x=5
    => x∈{2;5}
    C. (x-1)(x^2 +1)=0
    TH1: 
    <=> x-1=0
    <=> x=1
    TH2:
    <=> x^2 +1=0
    <=> x^2 =-1 (Vô lí)
    => x=1

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222-9+11+12:2*14+14 = ? ( )

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