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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: tìm x;y nguyên (3x-5y)(3x+2y+1)=9

Home/ Toán Lớp 8: tìm x;y nguyên (3x-5y)(3x+2y+1)=9

Toán Lớp 8: tìm x;y nguyên (3x-5y)(3x+2y+1)=9

Tháng Mười 21, 2022 Toán học 1 Comment 0 views

Toán Lớp 8: tìm x;y nguyên
(3x-5y)(3x+2y+1)=9

Comments ( 1 )

  1. hoaiphuong85
    hoaiphuong85
    21 Tháng Mười, 2022 at 11:03 chiều
    Reply
    $MID$
    $có$ $thể:$ \(\left[ \begin{array}{l}3x-5y=3\\3x+2y+1=3\end{array} \right.\)
    $=>$ \(\left[ \begin{array}{l}3x-5y-3=0\\3x+2y+1-3=0\end{array} \right.\)
    $=>$\(\left[ \begin{array}{l}(3x-3)-5y=0\\(3x-3)+2y+1=0\end{array} \right.\)
    $gọi:(3x-3)=a$
    $=>$\(\left[ \begin{array}{l}a-5y=0\\a+2y+1=0\end{array} \right.\)
    $=>$\(\left[ \begin{array}{l}a-y=0\\a+y=\frac{-1}{2}\end{array} \right.\)
    $=>do$$\left \{ {{x-y=0} \atop {x+y=\frac{-1}{2}}} \right.$
    $=>x=y$ $do:x+y=\frac{-1}{2}$
    $=>x=y=\frac{-1}{4}$
    $\frac{chúc-bạn-học-tốt}{mình-xin-hay-nhất-nha}$

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222-9+11+12:2*14+14 = ? ( )

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