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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: b) x^3 + 6x^2y + 12xy^2 + 9y^3 c) 9x^3 + 12x^2y + 6xy^2 + y^3

Toán Lớp 8: b) x^3 + 6x^2y + 12xy^2 + 9y^3
c) 9x^3 + 12x^2y + 6xy^2 + y^3

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
     b) x³ + 6x²y + 12xy² + 9y³
    = (x+2y)³ + y³
    = (x+2y+y)[(x+2y)² – y(x+2y) + y²]
    = (3y+x)(x²+4xy+4y² – xy – 2y² + y²)
    = (3y+x)(x² +3xy + 3y²)
    c) 9x³ + 12x²y + 6xy² + y³
    = x³ + 8x³ + 12x²y + 6xy² + y³
    = x³ + (2x+y)³
    = (x+2x+y)[x² – x(2x+y) + (2x+y)²]
    = (3x+y)(x² – 2x² – xy + 4x² + 4xy + y²)
    = (3x+y)(3x² + 3xy + y²)

  2. Giải đáp:
    b) x^3 + 6x^2y + 12xy^2 + 9y^3
    = x^3 + 6x^2y + 12xy^2 + 8y^3 + y^3
    =x^3 + 3.x^2 . 2y + 3.x . (2y)^2 + (2y)^3 + y^3
    = (x + 2y)^3 + y^3
    =(x+ 3y ) ( x + 4xy + 4y^2 – xy – 2y^2 + y^2 )
    = (x+ 3y)( x^2 + 3y^2 + 3xy)
    c) 9x^3 + 12x^2y + 6xy^2 + y^3
    = x^3 + 8x^3 + 12xy + 6xy^2 + y^3
    = x^3 + ( 2x + y)^3
    = (3x + y)( x^2 – 2x^2 – xy + 4x^2 – 4xy + y^2)
    = (3x + y)(3x^2 – 5xy + y^2)

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222-9+11+12:2*14+14 = ? ( )

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