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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Bài 3 Cho `1^2`+`2^2`+`3^2`+-+`10^2`=358 Hãy tính S=`100^2`+`200^2`+`300^2`+-. +`1000^2`

Toán Lớp 7: Bài 3 Cho 1^2+2^2+3^2+….+10^2=358
Hãy tính S=100^2+200^2+300^2+….. +1000^2

Comments ( 2 )

  1. $\\$
    S=100^2 +200^2+ … + 1000^2
    -> S = (1 . 100)^2 + (2 . 100)^2 + … + (10 . 100)^2
    ->S = 1^2 . 100^2 + 2^2 . 100^2 + … + 10^2 . 100^2
    ->S=100^2 . (1^2 +2^2+…+10^2)
    ->S = 100^2 . 358 (Do 1^2 +2^2+…+10^2=358)
    ->S=100 00 . 358
    ->S=35800 00
    Vậy S=35800 00 khi 1^2 +2^2+…+10^2=358
     

  2. Ta có: S = $100^{2}$ + $200^{2}$ + $300^{2}$ + … + $1000^{2}$ 
                 = $(1.100)^{2}$ + $(2.100)^{2}$ + $(3.100)^{2}$ + … + $(100.100)^{2}$
                 =$100^{2}$.$1^{2}$ + $100^{2}$.$2^{2}$ + $100^{2}$.$3^{2}$ + … + $100^{2}$.$100^{2}$
                 = $100^{2}$.( $1^{2}$ + $2^{2}$ + $3^{2}$ + … + $100^{2}$)
                 = $100^{2}$. 358
                 = 3 580 000
     

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222-9+11+12:2*14+14 = ? ( )

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