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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Bài 1 so sánh (1/16)^100 và( 1/2)^500

Toán Lớp 7: Bài 1 so sánh (1/16)^100 và( 1/2)^500

Comments ( 2 )

  1. Ta có : $(\dfrac{1}{2})^{500}$ = $(\dfrac{1}{2})^{5.100}$ = $[(\dfrac{1}{2})^{5}]^{100}$ = $[(\dfrac{1^{5}}{2^{5}})]^{100}$ = $(\dfrac{1}{32})^{100}$
    Mà $(\dfrac{1}{32})^{100}$ < $(\dfrac{1}{16})^{100}$ ($\dfrac{1}{16}$>$\dfrac{1}{32}$ vì $16^{}$<$32^{}$)
    ⇒$(\dfrac{1}{16})^{100}$ > $(\dfrac{1}{2})^{500}$

  2. text{Giải đáp + Lời giải và giải thích chi tiết}
     text{Theo đề bài ta có:}
    (1/16)^100=[(1/2)^4]^100= (1/2)^400
    (1/2)^500
    Do (1/2)^400>(1/2)^500 nên:
    =>(1/16)^100>(1/2)^500
    Vậy (1/16)^100>(1/2)^500

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222-9+11+12:2*14+14 = ? ( )

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