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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: Giúp em với ạ cot ( 3x – 1 ) = – √3

Toán Lớp 11: Giúp em với ạ
cot ( 3x – 1 ) = – √3

Comments ( 2 )

  1. $\cot(3x-1)=-\sqrt{3}\\⇔3x-1=-\dfrac{π}{6}+kπ\\⇔x=\dfrac{1}{3}-\dfrac{π}{18}+\dfrac{kπ}{3}(k\in\mathbb{Z})$

  2. $cot(3x-1)=-\sqrt[]{3}$
    $⇔cot(3x-1)=cot\bigg(\dfrac{-\pi}{6}\bigg)$
    $⇔3x-1=\dfrac{-\pi}{6}+k\pi$
    $⇔3x=1-\dfrac{\pi}{6}+k\pi$
    $⇔x=\dfrac{1}{3}-\dfrac{\pi}{18}+\dfrac{k\pi}{3}(k∈Z)$

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222-9+11+12:2*14+14 = ? ( )

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