Toán Lớp 6: a) Tính:
A = 1 + 2 + 2^2 + … + 2^106
b) So sánh A với 2^107
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Toán Lớp 6: a) Tính:
A = 1 + 2 + 2^2 + … + 2^106
b) So sánh A với 2^107
Comments ( 2 )
2A = 2 + 2^2 + 2^3 + … + 2^107.
2A – A = (2 + 2^2 + 2^3 + … + 2^107) – (1 + 2 + 2^2 + … + 2^106).
A = 2^107 – 1.
b) $\text{Ta có}$ 2^107 > 2^107 – 1 = A.