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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: (x + 1)(2 –x)–(3x + 5)(x + 2)= -4x^2+ 1

Toán Lớp 8: (x + 1)(2 –x)–(3x + 5)(x + 2)= -4x^2+ 1

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
      (x+1)(2-x) – (3x+5)(x+2) = -4x^2 + 1
    -> 2x – x^2 + 2 – x – (3x^2 + 6x + 5x + 10) -(- 4x^2 +1) = 0
    -> 2x – x^2 + 2 – x – 3x^2 – 6x – 5x – 10 + 4x^2 – 1 = 0
    -> (x^2 – 3x^2 + 4x^2) + (2x – x – 6x – 5x ) + (2-10-1) =0
    -> -10x – 9 = 0
    -> -10x = 9
    -> x = -9/10
    Vậy S = {x|x=-9/10}

  2. (x+1)(2-x)-(3x+5)(x+2)=-4x^2+1
    ⇔2x-x^2+2-x-3x^2-6x-5x-10+4x^2-1=0
    ⇔-10x-9=0
    ⇔-10x=9
    ⇔x=-9/(10)
    Vậy S={-9/(10)}
     

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222-9+11+12:2*14+14 = ? ( )