Toán Lớp 11: Tìm txđ của hàm số y=tan2x/sinx+1 + cot(3x+Pi/6)
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Toán Lớp 11: Tìm txđ của hàm số y=tan2x/sinx+1 + cot(3x+Pi/6)
Comments ( 2 )
y = \dfrac{{\tan 2x}}{{\sin x + 1}} + \cot \left( {3x + \dfrac{\pi }{6}} \right)\\
DK:\left\{ \begin{array}{l}
\cos 2x \ne 0\\
\sin x + 1 \ne 0\\
\sin \left( {3x + \dfrac{\pi }{6}} \right) \ne 0
\end{array} \right.\\
\to \left\{ \begin{array}{l}
2x \ne \dfrac{\pi }{2} + k\pi \\
x \ne – \dfrac{\pi }{2} + k2\pi \\
3x + \dfrac{\pi }{6} \ne k\pi
\end{array} \right.\\
\to \left\{ \begin{array}{l}
x \ne \dfrac{\pi }{4} + \dfrac{{k\pi }}{2}\\
x \ne – \dfrac{\pi }{2} + k2\pi \\
x \ne – \dfrac{\pi }{{18}} + \dfrac{{k\pi }}{3}
\end{array} \right.\left( {k \in Z} \right)\\
\to TXD:D = R\backslash \left\{ { – \dfrac{\pi }{2} + k2\pi ; – \dfrac{\pi }{{18}} + \dfrac{{k\pi }}{3};\dfrac{\pi }{4} + \dfrac{{k\pi }}{2}} \right\}
\end{array}\)