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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 3x ² √24 x = 22 TÌM X Ạ HELPPP

Toán Lớp 8: 3x ² √24 x = 22
TÌM X Ạ
HELPPP

Comments ( 2 )

  1. $@Mốc$
    3x^{2}\sqrt{24}x = 22
    ⇔ 3\sqrt{4.6}.x^{3} = 22
    ⇔ 6\sqrt{6}.x^{3} = 22
    ⇔ $x^{3}$ = $\dfrac{11}{3\sqrt[]{6}}$
    ⇔ $x$ = $\sqrt[3]{\dfrac{11}{3\sqrt[]{6}}}$ 
    $#chucbanhoctotnhe;333$

  2. Giải đáp+Lời giải và giải thích chi tiết:
    3x^2\sqrt{24}x=22
    <=>3x^3\sqrt{2^2 .6}=22
    <=>6x^3\sqrt{6}=22
    <=>x^3=\frac{11}{3\sqrt{6}}
    <=>x^3=(\root[3]{\frac{11}{3\sqrt{6}}})^3
    <=>x=\root[3]{\frac{11}{3\sqrt{6]}} 
    Vậy x=\root[3]{\frac{11}{3\sqrt{6]}} 

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222-9+11+12:2*14+14 = ? ( )