Toán Lớp 11: sin ( x + bi / 3 ) = – căn 3/2
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Toán Lớp 11: sin ( x + bi / 3 ) = – căn 3/2
giúp ae
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\sin \left( {x + \dfrac{\pi }{3}} \right) = – \dfrac{{\sqrt 3 }}{2}\\
\Leftrightarrow \sin \left( {x + \dfrac{\pi }{3}} \right) = \sin \left( { – \dfrac{\pi }{3}} \right)\\
\Leftrightarrow \left[ \begin{array}{l}
x + \dfrac{\pi }{3} = – \dfrac{\pi }{3} + k2\pi \\
x + \dfrac{\pi }{3} = \dfrac{{4\pi }}{3} + k2\pi
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l}
x = – \dfrac{{2\pi }}{3} + k2\pi \\
x = \pi + k2\pi
\end{array} \right.\left( {k \in Z} \right)
\end{array}$