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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tìm x, biết: a) `(2x + 3)(x – 4) + (x – 5)(x – 2) = (3x – 5)(x – 4)` b) `2x^2 + 3(x – 1)(x + 1) = 5x(x + 1)`

Toán Lớp 8: Tìm x, biết:
a) (2x + 3)(x – 4) + (x – 5)(x – 2) = (3x – 5)(x – 4)
b) 2x^2 + 3(x – 1)(x + 1) = 5x(x + 1)

Comments ( 2 )

  1. a)
    (2x+3)(x-4) + (x-5)(x-2)= (3x-5)(x-4)
    => (2x . x -2x . 4 + 3 . x – 3.4) + (x.x-x.2-5.x+5.2) = 3x . x – 3x . 4 – 5 . x + 5.4
    => (2x^2 – 8x + 3x – 12) + (x^2 – 2x – 5x + 10) = 3x^2 – 12x – 5x + 20
    => 2x^2 – 8x  + 3x – 12 + x^2 – 2x – 5x +10 – 3x^2 + 12x + 5x – 20=0
    => (2x^2+ x^2 – 3x^2) + (3x – 8x – 2x – 5x + 12x + 5x) + (10 – 12-20) =0
    => 5x – 22 =0
    => 5x=22
    =>x=22/5
    Vậy x=22/5
    b)
    2x^2 + 3 (x-1)(x+1) = 5x (x+1)
    => 2x^2 + 3 (x^2 -1) = 5x . x + 5x . 1
    => 2x^2 + 3x^2 – 3= 5x^2 + 5x
    => 2x^2 + 3x^2 – 5x^2 – 5x = 3
    => -5x=3
    =>x=-3/5
    Vậy x=-3/5

  2. Giải đáp + Lời giải và giải thích chi tiết !
    a)
    (2x+3)(x-4)+(x-5)(x-2) = (3x-5)(x-4)
    <=> 2x^2-8x+3x-12+x^2-2x-5x+10 = 3x^2-12x-5x+20
    <=> (2x^2+x^2)+(-8x+3x-2x-5x)+(-12+10)-3x^2+12x+5x-20 = 0
    <=> 3x^2-12x-2-3x^2+12x+5x-20 = 0
    <=> (3x^2-3x^2)+(-12x+12x+5x)+(-2-20) = 0
    <=> 5x-22 = 0
    <=> 5x = 22
    <=> x = (22)/5
    Vậy S= {(22)/5}
    b)
    2x^2+3(x-1)(x+1) = 5x(x+1)
    <=> 2x^2+3(x^2-1) = 5x^2+5x
    <=> 2x^2+3x^2-3-5x^2-5x = 0
    <=> (2x^2+3x^2-5x^2)-5x-3 = 0
    <=> -5x = 3
    <=> x = -(3)/5
    Vậy S= {-(3)/5}

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222-9+11+12:2*14+14 = ? ( )

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