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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: $\frac{√26}{√13}$ – $\frac{2+√2 }{√2+ 1}$ – $\frac{7 }{√2 – 3}$

Tháng Tám 27, 2022 Toán học 2 Comments 0 views

Toán Lớp 9: $\frac{√26}{√13}$ – $\frac{2+√2 }{√2+ 1}$ – $\frac{7 }{√2 – 3}$

Comments ( 2 )

  1. khanhlanchau
    khanhlanchau
    27 Tháng Tám, 2022 at 9:49 chiều
    Reply
    Lời giải:
     \(\begin{array}{l}\dfrac{\sqrt{26}}{\sqrt{13}}-\dfrac{2+\sqrt{2}}{\sqrt{2}+1}-\dfrac{7}{\sqrt{2}-3}\\=\sqrt{\dfrac{26}{13}}-\dfrac{\sqrt{2}(\sqrt{2}+1)}{\sqrt{2}+1}+\dfrac{7(3+\sqrt{2})}{9-2}\\=\sqrt{2}-\sqrt{2}+(3+\sqrt{2})\\=3+\sqrt{2}\end{array}\)

  2. tuyethutanhthu
    tuyethutanhthu
    27 Tháng Tám, 2022 at 9:48 chiều
    Reply
    $\displaystyle \begin{array}{{>{\displaystyle}l}} \frac{\sqrt{26}}{\sqrt{13}} -\frac{2+\sqrt{2}}{\sqrt{2} +1} -\frac{7}{\sqrt{2} -3}\\ =\sqrt{\frac{26}{13}} -\frac{\sqrt{2}\left(\sqrt{2} +1\right)}{\sqrt{2} +1} +\frac{7\left( 3+\sqrt{2}\right)}{3-2}\\ =\sqrt{2} -\sqrt{2} +21+7\sqrt{2}\\ =21+7\sqrt{2} \ \\ \end{array}$

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222-9+11+12:2*14+14 = ? ( )

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