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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: $\sqrt{6,8^2 – 3,2^2}$ Tớ sẽ bl và hỏi

Toán Lớp 9: $\sqrt{6,8^2 – 3,2^2}$
Tớ sẽ bl và hỏi

Comments ( 2 )

  1. #tnvt
    \sqrt{6,8^2-3,2^2}
    =\sqrt{(6,8-3,2)(6,8+3,2)}
    =\sqrt{3,6 .10}
    =\sqrt{36}
    =\sqrt{6^2}
    =|6|
    =6

  2. \sqrt{6,8^2 – 3,2^2}
    =\sqrt{(6,8-3,2)(6,8+3,2)}
    =\sqrt{3,6.10}
    =\sqrt{36}
    =\sqrt{(6)^2}
    =|6|
    =6
    *Áp dụng
    a^2 – b^2=(a-b)(a+b)
    \sqrt{A^2}=|A|
     

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222-9+11+12:2*14+14 = ? ( )