Toán Lớp 9: Rút gọn : C= $\frac{2}{\sqrt[]{3}-\sqrt[]{2}}$ + $\frac{1}{3+2\sqrt[]{2}}$
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Toán Lớp 9: Rút gọn : C= $\frac{2}{\sqrt[]{3}-\sqrt[]{2}}$ + $\frac{1}{3+2\sqrt[]{2}}$
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\quad C = \dfrac{2}{\sqrt 3- \sqrt2} + \dfrac{1}{3 + 2\sqrt2}\\
\to C = \dfrac{2\left(\sqrt3 + \sqrt2\right)}{\left(\sqrt3 – \sqrt2\right)\left(\sqrt3 + \sqrt2\right)} + \dfrac{3 – 2\sqrt2}{\left(3 + 2\sqrt2\right)\left(3 – 2\sqrt2\right)}\\
\to C = \dfrac{2\sqrt3 + 2\sqrt2}{3 – 2} + \dfrac{3 – 2\sqrt2}{9 – 8}\\
\to C = 2\sqrt3 + 2\sqrt2 + 3 – 2\sqrt2\\
\to C = 3 + 2\sqrt3
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