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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: Rút gọn biểu thức: $\text{1:(}$$\frac{a +2}{a\sqrt{a}+1}$+ $\frac{\sqrt{a}-1}{a-\sqrt{a}+1} – $ $\frac{\sqrt{a}-1}{a-1})với (a$$\geq0

Toán Lớp 9: Rút gọn biểu thức: $\text{1:(}$$\frac{a +2}{a\sqrt{a}+1}$+ $\frac{\sqrt{a}-1}{a-\sqrt{a}+1} – $ $\frac{\sqrt{a}-1}{a-1})với (a$$\geq0, a$$\neq1)$

Comments ( 1 )

  1. Giải đáp:
    $\dfrac{a-\sqrt{a}+1}{\sqrt{a}}.$
    Lời giải và giải thích chi tiết:
    $1:\left(\dfrac{a+2}{a\sqrt{a}+1}+\dfrac{\sqrt{a}-1}{a-\sqrt{a}+1}-\dfrac{\sqrt{a}-1}{a-1}\right)(a \ge0 ;a \ne 1)\\ =1:\left(\dfrac{a+2}{(\sqrt{a}+1)(a-\sqrt{a}+1)}+\dfrac{(\sqrt{a}-1)(\sqrt{a}+1)}{(\sqrt{a}+1)(a-\sqrt{a}+1)}-\dfrac{\sqrt{a}-1}{(\sqrt{a}-1)(\sqrt{a}+1)}\right)\\ =1:\left(\dfrac{a+2}{(\sqrt{a}+1)(a-\sqrt{a}+1)}+\dfrac{a-1}{(\sqrt{a}+1)(a-\sqrt{a}+1)}-\dfrac{1}{\sqrt{a}+1}\right)\\ =1:\dfrac{a+2+a-1-(a-\sqrt{a}+1)}{(\sqrt{a}+1)(a-\sqrt{a}+1)}\\ =1:\dfrac{a+\sqrt{a}}{(\sqrt{a}+1)(a-\sqrt{a}+1)}\\ =1:\dfrac{\sqrt{a}(\sqrt{a}+1)}{(\sqrt{a}+1)(a-\sqrt{a}+1)}\\ =1:\dfrac{\sqrt{a}}{a-\sqrt{a}+1}\\ =\dfrac{a-\sqrt{a}+1}{\sqrt{a}}.$

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222-9+11+12:2*14+14 = ? ( )