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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: rút gọn biểu thức `(sqrt{14}-sqrt{2}) sqrt{4+sqrt{7}}`

Toán Lớp 9: rút gọn biểu thức
(sqrt{14}-sqrt{2}) sqrt{4+sqrt{7}}

Comments ( 2 )

  1. ($\sqrt{14}$-$\sqrt{2}$).$\sqrt{4+\sqrt{7}}$
    = $\sqrt{(\sqrt{14}-\sqrt{2})².(4+\sqrt{7}}$
    = $\sqrt{(16-4\sqrt{7})(4+\sqrt{7}}$
    = 2$\sqrt{4²-(\sqrt{7})²}$
    = 2$\sqrt{16-7}$
    = 6
     

  2. ($\sqrt{14}$ – $\sqrt{2}$).$\sqrt{4 + \sqrt{7}}$ 
    = $\sqrt{2}$.($\sqrt{7}$ – 1).$\sqrt{\frac{2.(4 + \sqrt{7})}{2}}$ 
    = $\sqrt{2}$.($\sqrt{7}$ – 1).$\sqrt{\frac{8 + 2\sqrt{7}}{2}}$
    = $\sqrt{2}$.($\sqrt{7}$ – 1).$\sqrt{\frac{7 + 2\sqrt{7} + 1}{2}}$ 
    = $\sqrt{2}$.($\sqrt{7}$ – 1).$\sqrt{\frac{(\sqrt{7} + 1)²}{2}}$
    = $\sqrt{2}$.($\sqrt{7}$ – 1).$\frac{|\sqrt{7} + 1|}{\sqrt{2}}$
    = $\sqrt{2}$.($\sqrt{7}$ – 1).$\frac{\sqrt{7} + 1}{\sqrt{2}}$
    = ($\sqrt{7}$ – 1).($\sqrt{7}$ + 1)
    = 7 – 1
    = 6
    Chúc bạn học tốt
     

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222-9+11+12:2*14+14 = ? ( )

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