Toán Lớp 9: Rút gọn:
$A$ = $\frac{3+\sqrt{9x}-3}{x+\sqrt{x}-2}$ – $\frac{\sqrt{x}+1}{\sqrt{x}+2}$ +$\frac{\sqrt{x}+2}{1-\sqrt{x}}$
Giúp tớ với, mình cảm ơn hứa vote tthn cho ai nhanh nhất :((((
Leave a reply
Register Now
Login
Lost Password
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Toán Lớp 9: Rút gọn:
$A$ = $\frac{3+\sqrt{9x}-3}{x+\sqrt{x}-2}$ – $\frac{\sqrt{x}+1}{\sqrt{x}+2}$ +$\frac{\sqrt{x}+2}{1-\sqrt{x}}$
Giúp tớ với, mình cảm ơn hứa vote tthn cho ai nhanh nhất :((((
Comments ( 1 )
A=(3x+sqrt{9x}-3)/(x+sqrt{x}-2)-(sqrt{x}+1)/(sqrt{x}+2)+(sqrt{x}+2)/(1-sqrt{x})
=(3x+3sqrt{x}-3)/((sqrt{x}-1)(sqrt{x}+2))-((sqrt{x}-1)(sqrt{x}+1))/((sqrt{x}-1)(sqrt{x}+2))-((sqrt{x}+2)^2)/((sqrt{x}-1)(sqrt{x}+2))
=(3x+3sqrt{x}-3-x+1-x-4sqrt{x}-4)/((sqrt{x}-1)(sqrt{x}+2))
=(x-sqrt{x}-6)/((sqrt{x}-1)(sqrt{x}+2))
=((sqrt{x}+2)(sqrt{x}-3))/((sqrt{x}-1)(sqrt{x}+2))
=(sqrt{x}-3)/(sqrt{x}-1)
Vậy A=(sqrt{x}-3)/(sqrt{x}-1).