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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: +$\frac{-6}{căn7+3}$ +$\frac{8}{căn7-3}$ +$\frac{12}{căn7}$

Toán Lớp 9: +$\frac{-6}{căn7+3}$ +$\frac{8}{căn7-3}$ +$\frac{12}{căn7}$

Comments ( 2 )

  1. (-6)/(sqrt7+3)+8/(sqrt7-3)+12/sqrt7 
    =(-6sqrt7(sqrt7-3))/(sqrt7(sqrt7+3)(sqrt7-3))+(8sqrt7(sqrt7+3))/(sqrt7(sqrt7+3)(sqrt7-3))+(12(sqrt7+3)(sqrt7-3))/(sqrt7(sqrt7+3)(sqrt7-3))
    =(-42+18sqrt7+56+24sqrt7+12(7-9))/(sqrt7(7-9))
    =(42sqrt7+14-24)/(sqrt7(7-9))         
    =(42sqrt7-10)/(-2sqrt7)                
    =(2(21sqrt7-5))/(-2sqrt7)       
    =-(21sqrt7-5)/sqrt7            
    =(-sqrt7(21sqrt7-5))/(sqrt7.sqrt7)          
    =(-147+sqrt7)/7                 

  2. Giải đáp:
     (-6)/(\sqrt{7} + 3) + 8/(\sqrt{7} – 3) + 12/(\sqrt{7}) = (-147 +5  \sqrt{7})/7
    Lời giải và giải thích chi tiết:
     (-6)/(\sqrt{7} + 3) + 8/(\sqrt{7} – 3) + 12/(\sqrt{7})
    = (-6 . \sqrt{7} . (\sqrt{7} – 3) + 8 . \sqrt{7} . (\sqrt{7} + 3) + 12 (\sqrt{7} + 3)(\sqrt{7}- 3) )/( \sqrt{7} (\sqrt{7} – 3)(\sqrt{7} + 3))
    = ( – 6 . \sqrt{7} . \sqrt{7} + 6 . 3 . \sqrt{7} + 8. \sqrt{7} . \sqrt{7} + 8 . 3 . \sqrt{7} + 12 . [(\sqrt{7})^2  – (\sqrt{3})^2])/( \sqrt{7} . [ (\sqrt{7})^2 – 3^2])
    =  ( – 6 . 7 + 18 \sqrt{7} + 8  .7 + 24 \sqrt{7} + 12 (7-9))/(\sqrt{7} (7-9))
    =  (-42 + 18 \sqrt{7} + 56 + 24 \sqrt{7} – 24 )/( -2 \sqrt{7})
    = (42\sqrt{7} -10 )/(-2 \sqrt{7})
    = (2 (21 \sqrt{7} -5 ))/(- 2 \sqrt{7})
    = ( – (21 \sqrt{7} – 5 ))/(\sqrt{7})
    = (- \sqrt{7} . 21 \sqrt{7} + \sqrt{7} . 5)/( (\sqrt{7} . \sqrt{7})
    = (-147 +5  \sqrt{7})/7

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222-9+11+12:2*14+14 = ? ( )

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