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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: $\frac{6}{1-\sqrt{3}}$-$\frac{2\sqrt{3}}{2+\sqrt{3}}$

Toán Lớp 9: $\frac{6}{1-\sqrt{3}}$-$\frac{2\sqrt{3}}{2+\sqrt{3}}$

Comments ( 2 )

  1. ~ Bạn tham khảo ~
    (6)/(1-\sqrt(3))-(2\sqrt(3))/(2+\sqrt(3))
    =(6(2+\sqrt3))/((1-\sqrt(3))(2+\sqrt3))-(2\sqrt(3)(1-\sqrt(3)))/((1-\sqrt(3))(2+\sqrt3))
    =(12+6\sqrt3)/(-1-\sqrt3)-(2\sqrt(3)-6)/(-1-\sqrt3)
    =(12+6\sqrt3-2\sqrt(3)+6)/(-1-\sqrt3)
    =(18+4\sqrt3)/(-1-\sqrt3)
    = 3-7\sqrt3

  2. Giải đáp:
    6/(1-sqrt{3})-(2sqrt{3})/(2+sqrt{3})=3-7sqrt{3}
    Lời giải và giải thích chi tiết:
    6/(1-sqrt{3})-(2sqrt{3})/(2+sqrt{3})
    =(6.(1+sqrt{3}))/((1-sqrt{3})(1+sqrt{3}))-(2sqrt{3}.(2-sqrt{3}))/((2+sqrt{3})(2-sqrt{3}))
    =(2.3.(1+sqrt{3}))/(1-3)-(4sqrt{3}-6)/(4-3)
    =(2.3.(1+sqrt{3}))/(-1 . 2)-(4sqrt{3}-6)/1
    =-3.(1+sqrt{3})-4sqrt{3}+6
    =-3-3sqrt{3}-4sqrt{3}+6
    =3-7sqrt{3}

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222-9+11+12:2*14+14 = ? ( )

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