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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: chứng minh đẳng thức 1/sin²x+1/cos²x=tan²x+cot²x+2 Giúp mình vs ạ mình cần gấpp

Toán Lớp 9: chứng minh đẳng thức 1/sin²x+1/cos²x=tan²x+cot²x+2
Giúp mình vs ạ mình cần gấpp

Comments ( 2 )

  1. ~rai~
    \(\dfrac{1}{\sin^2x}+\dfrac{1}{\cos^2x}=\tan^2x+\cot^2x+2.\\\text{Xét VT=}\dfrac{1}{\sin^2x}+\dfrac{1}{\cos^2x}\\\quad\quad\quad=\dfrac{\sin^2x+\cos^2x}{\sin^2x}+\dfrac{\sin^2x+\cos^2x}{\cos^2x}\\\quad\quad\quad=\dfrac{\sin^2x}{\sin^2x}+\dfrac{\cos^2x}{\sin^2x}+\dfrac{\sin^2x}{\cos^2x}+\dfrac{\cos^2x}{\cos^2x}\\\quad\quad\quad=1+\cot^2x+\tan^2x+1\\\quad\quad\quad=\tan^2x+\cot^2x+2\\\quad\quad\quad=VP.\\\Rightarrow \dfrac{1}{\sin^2x}+\dfrac{1}{\cos^2x}=\tan^2x+\cot^2x+2.(đpcm)\\\text{Giải thích:Các công thức đã dùng để chứng minh:}\\+)\sin^2\alpha+\cos^2\alpha=1.\\+)\dfrac{\sin\alpha}{\cos\alpha}=\tan\alpha.\\+)\dfrac{\cos\alpha}{\sin\alpha}=\cot\alpha.\)

  2. $\dfrac{1}{sin^2x}+\dfrac{1}{cos^2}=tan^2x+cot^2x+2$
    $VT=1+cot^2x+1+tan^2x$
    $=tan^2x+cot^2x+2=VP$(ĐPCM)

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222-9+11+12:2*14+14 = ? ( )

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