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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: (3 √2+6 / √12+2 – √54/3).2/ √6=-1

Tháng Mười Hai 6, 2022 Toán học 2 Comments 0 views

Toán Lớp 9: (3 √2+6 / √12+2 – √54/3).2/ √6=-1

Comments ( 2 )

  1. mytamhoang
    mytamhoang
    6 Tháng Mười Hai, 2022 at 6:23 chiều
    Reply
    $(\dfrac{3\sqrt{2}+6}{\sqrt{12}+2}-\dfrac{\sqrt{54}}{3}).\dfrac{2}{\sqrt{6}}$
    $=(\dfrac{\sqrt{2}(3+3\sqrt{2})}{\sqrt{2}(\sqrt{6}+\sqrt{2})}-\sqrt{6}).\dfrac{2}{\sqrt{6}}$
    $=(\dfrac{(3+3\sqrt{2})(\sqrt{6}-\sqrt{2})}{(\sqrt{6}+\sqrt{2})(\sqrt{6}-\sqrt{2})}-\sqrt{6}).\dfrac{2}{\sqrt{6}}$
    $=(\dfrac{3\sqrt{6}-3\sqrt{2}+6\sqrt{3}-6}{4}-\sqrt{6}).\dfrac{2}{\sqrt{6}}$
    $=\dfrac{3-\sqrt{3}+3\sqrt{2}-\sqrt{6}}{2}-2$
    $=\dfrac{-1-\sqrt{3}+3\sqrt{2}-\sqrt{6}}{2}$

  2. khanhlanchau
    khanhlanchau
    6 Tháng Mười Hai, 2022 at 6:23 chiều
    Reply
    Giải đáp:
    ((3sqrt2+6)/(2+sqrt{12})-sqrt{54}/3)*2/sqrt6
    =((3(sqrt2+2))/(2+2sqrt3)-sqrt{9.6}/3)*2/sqrt6
    =((3sqrt2(sqrt2+1))/(2(sqrt3+1))-sqrt6)*2/sqrt6
    =((3sqrt2(sqrt2+1)(sqrt3-1))/(2.2)-sqrt6)*2/sqrt6
    =((3sqrt2(sqrt6-sqrt2+sqrt3-1))/4-sqrt6)*2/sqrt6
    =(sqrt3(sqrt6-sqrt2+sqrt3-1))/2-2
    =(-sqrt6+3+3sqrt2-sqrt3-4)/2
    =(3sqrt2-sqrt3-sqrt6-1)/2

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222-9+11+12:2*14+14 = ? ( )

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